Probability and Stochastic Homework 4 (Papoulis Chapter 5) 1. Suppose π = π₯ 2 β 3π₯ + 1 and: X p -2 1 5 -1 1 10 0 1 5 1 1 10 2 2 5 (a) Find πΈ (π). (b) Find πππ(π₯ ). 2. The RV π₯ is a uniform in the interval (0, 1). Find the density of the π¦ = β ln π₯. [Problem 5-6 of Papoulis] 3. Prove: π 2 = πΈ (π₯ 2 ) β π2 . 4. For Bernoulli trial, prove: π 2 = πππ (Hint: Use previous question) 5. Show that, if the RV π₯ has a Cauchy density with πΌ = 1 and π¦ = tanβ1 π₯, then π¦ is uniform in the interval ( βπ π 2 , 2 ). [Problem 5-11 of Papoulis] 6. Given that RV π₯ of continuous type, we form the RV π¦ = π(π₯ ). Find ππ¦ (π¦) if π(π₯ ) = 2πΉπ₯ (π₯ ) + 4. [Problem 5-14 of Papoulis] 7. We place at random 200 points in the interval (0, 100). The distance from 0 to the first random point is an RV π§. Find πΉπ§ (π§) exactly. [Problem 5-7 of Papoulis] 8. We place at random 200 points in the interval (0, 100). The distance from 0 to the first random point is an RV π§. Find πΉπ§ (π§) using the Poisson approximation. [Problem 5-7 of Papoulis] 9. The random variable π₯ is uniform in the interval (β2π, 2π). Find ππ¦ (π¦) if π¦ = π₯ 3 . [Problem 5-12 of Papoulis] 10. The random variable π₯ is uniform in the interval (β2π, 2π). Find ππ¦ (π¦) if π¦ = 2 sin(3π₯ + 40°). [Problem 5-12 of Papoulis] 11. For π(π, π), determine Probability-generating function. 12. Determine Probability-generating function for Poisson distribution (with π parameter).
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