Chapter 8 Resource Masters StudentWorks PlusTM includes the entire Student Edition text along with the worksheets in this booklet. TeacherWorks PlusTM includes all of the materials found in this booklet for viewing, printing, and editing. Cover: Jason Reed/Photodisc/Getty Images Copyright © by The McGraw-Hill Companies, Inc. All rights reserved. Permission is granted to reproduce the material contained herein on the condition that such materials be reproduced only for classroom use; be provided to students, teachers, and families without charge; and be used solely in conjunction with the Glencoe Precalculus program. Any other reproduction, for sale or other use, is expressly prohibited. Send all inquiries to: Glencoe/McGraw-Hill 8787 Orion Place Columbus, OH 43240 - 4027 ISBN: 978-0-07-893809-2 MHID: 0-07-893809-0 Printed in the United States of America. 2 3 4 5 6 7 8 9 10 079 18 17 16 15 14 13 12 11 10 Contents Teacher’s Guide to Using the Chapter 8 Resource Masters ........................................... iv Lesson 8-5 Student-Built Glossary ....................................... 1 Anticipation Guide (English) .............................. 3 Anticipation Guide (Spanish) ............................. 4 Dot and Cross Products of Vectors in Space Study Guide and Intervention .......................... 26 Practice............................................................ 28 Word Problem Practice ................................... 29 Enrichment ...................................................... 30 Graphing Calculator Activity ............................ 31 Lesson 8-1 Assessment Chapter Resources Introduction to Vectors Study Guide and Intervention ............................ 5 Practice.............................................................. 7 Word Problem Practice ..................................... 8 Enrichment ........................................................ 9 Vectors in the Coordinate Plane Study Guide and Intervention .......................... 10 Practice............................................................ 12 Word Problem Practice ................................... 13 Enrichment ...................................................... 14 Chapter 8 Quizzes 1 and 2 ............................. 33 Chapter 8 Quizzes 3 and 4 ............................. 34 Chapter 8 Mid-Chapter Test ............................ 35 Chapter 8 Vocabulary Test ............................. 36 Chapter 8 Test, Form 1 ................................... 37 Chapter 8 Test, Form 2A................................. 39 Chapter 8 Test, Form 2B................................. 41 Chapter 8 Test, Form 2C ................................ 43 Chapter 8 Test, Form 2D ................................ 45 Chapter 8 Test, Form 3 ................................... 47 Chapter 8 Extended-Response Test ............... 49 Standardized Test Practice ............................. 50 Lesson 8-3 Answers ........................................... A1–A23 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Lesson 8-2 Dot Products and Vector Projections Study Guide and Intervention .......................... 15 Practice............................................................ 17 Word Problem Practice ................................... 18 Enrichment ...................................................... 19 Lesson 8-4 Vectors in Three-Dimensional Space Study Guide and Intervention .......................... 20 Practice............................................................ 22 Word Problem Practice ................................... 23 Enrichment ...................................................... 24 Graphing Calculator Activity ............................ 25 Chapter 8 iii Glencoe Precalculus Teacher’s Guide to Using the Chapter 8 Resource Masters The Chapter 8 Resource Masters includes the core materials needed for Chapter 8. These materials include worksheets, extensions, and assessment options. The answers for these pages appear at the back of this booklet. Practice This master closely follows the types of problems found in the Exercises section of the Student Edition and includes word problems. Use as an additional practice option or as homework for second-day teaching of the lesson. Chapter Resources Student-Built Glossary (pages 1–2) These masters are a student study tool that presents up to twenty of the key vocabulary terms from the chapter. Students are to record definitions and/or examples for each term. You may suggest that students highlight or star the terms with which they are not familiar. Give this to students before beginning Lesson 8-1. Encourage them to add these pages to their mathematics study notebooks. Remind them to complete the appropriate words as they study each lesson. Word Problem Practice This master includes additional practice in solving word problems that apply to the concepts of the lesson. Use as an additional practice or as homework for second-day teaching of the lesson. Enrichment These activities may extend the concepts of the lesson, offer an historical or multicultural look at the concepts, or widen students’ perspectives on the mathematics they are learning. They are written for use with all levels of students. Graphing Calculator, TI–Nspire Calculator, or Spreadsheet Activities These activities present ways in which technology can be used with the concepts in some lessons of this chapter. Use as an alternative approach to some concepts or as an integral part of your lesson presentation. Lesson Resources Study Guide and Intervention These masters provide vocabulary, key concepts, additional worked-out examples and Guided Practice exercises to use as a reteaching activity. It can also be used in conjunction with the Student Edition as an instructional tool for students who have been absent. Chapter 8 iv Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Anticipation Guide (pages 3–4) This master, presented in both English and Spanish, is a survey used before beginning the chapter to pinpoint what students may or may not know about the concepts in the chapter. Students will revisit this survey after they complete the chapter to see if their perceptions have changed. Leveled Chapter Tests Assessment Options The assessment masters in the Chapter 8 Resource Masters offer a wide range of assessment tools for formative (monitoring) assessment and summative (final) assessment. • Form 1 contains multiple-choice questions and is intended for use with below grade level students. • Forms 2A and 2B contain multiple-choice questions aimed at on grade level students. These tests are similar in format to offer comparable testing situations. • Forms 2C and 2D contain free-response questions aimed at on grade level students. These tests are similar in format to offer comparable testing situations. • Form 3 is a free-response test for use with above grade level students. All of the above mentioned tests include a free-response Bonus question. Quizzes Four free-response quizzes offer assessment at appropriate intervals in the chapter. Mid-Chapter Test This one-page test provides an option to assess the first half of the chapter. It parallels the timing of the Mid-Chapter Quiz in the Student Edition and includes both multiple-choice and free-response questions. Vocabulary Test This test is suitable for all students. It includes a list of vocabulary words and questions to assess students’ knowledge of those words. This can also be used in conjunction with one of the leveled chapter tests. Extended-Response Test Performance assessment tasks are suitable for all students. Sample answers are included for evaluation. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Standardized Test Practice These three pages are cumulative in nature. It includes two parts: multiple-choice questions with bubble-in answer format and short-answer free-response questions. Answers • The answers for the Anticipation Guide and Lesson Resources are provided as reduced pages. • Full-size answer keys are provided for the assessment masters. Chapter 8 v Glencoe Precalculus NAME DATE 8 PERIOD This is an alphabetical list of key vocabulary terms you will learn in Chapter 8. As you study this chapter, complete each term’s definition or description. Remember to add the page number where you found the term. Add these pages to your Precalculus Study Notebook to review vocabulary at the end of the chapter. Vocabulary Term Found on Page Definition/Description/Example component form components cross product direction Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. dot product equivalent vectors initial point magnitude opposite vectors ordered triple (continued on the next page) Chapter 8 1 Glencoe Precalculus Chapter Resources Student-Built Glossary NAME DATE 8 PERIOD Student-Built Glossary Vocabulary Term Found on Page Definition/Description/Example orthogonal parallel vectors quadrant bearing resultant standard position Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. terminal point true bearing unit vector vector z-axis Chapter 8 2 Glencoe Precalculus NAME 8 DATE PERIOD Anticipation Guide Step 1 Before you begin Chapter 8 • Read each statement. • Decide whether you Agree (A) or Disagree (D) with the statement. • Write A or D in the first column OR if you are not sure whether you agree or disagree, write NS (Not Sure). STEP 1 A, D, or NS STEP 2 A or D Statement 1. Scalars have both magnitude and direction. 2. Vectors can be represented by directed line segments. 3. The initial point of a vector is the point where the vector starts. 4. Vectors can be used to represent forces applied at an angle. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 5. When vectors are combined the result is a scalar. 6. Any vector can be broken down into horizontal and vertical components. 7. To add two vectors algebraically, add all of the numbers in the first vector together. Then add all of the numbers in the second vector together. 8. Trigonometric ratios sometimes need to be used when working with vectors. 9. The dot product of two vectors is a scalar. 10. Vectors can be used to represent forces in three-dimensional space. 11. When finding torque, the dot product is used. 12. The area of a parallelogram can be found using dot products. Step 2 After you complete Chapter 8 • Reread each statement and complete the last column by entering an A or a D. • Did any of your opinions about the statements change from the first column? • For those statements that you mark with a D, use a piece of paper to write an example of why you disagree. Chapter 8 3 Glencoe Precalculus Chapter Resources Vectors NOMBRE 8 FECHA PERÍODO Ejercicios preparatorios Identidades y ecuaciones trigonométricas Paso 1 Antes de que comiences el Capítulo 8 • Lee cada enunciado. • Decide si estás de acuerdo (A) o en desacuerdo (D) con el enunciado. • Escribe A o D en la primera columna O si no estás seguro(a), escribe NS (no estoy seguro(a)). PASO 1 A, D o NS PASO 2 AoD Enunciado 1. Los escalares tienen tanto magnitud como dirección. 2. Los vectores se pueden representar con segmentos de recta con dirección. 3. El punto inicial de un vector es el punto donde comienza dicho vector. 4. Los vectores se pueden usar para representar fuerzas aplicadas en ángulo. 5. Los escalares son el resultado de la combinación de vectores. 6. Todo vector puede ser separado en un componente vertical y uno 8. 9. 10. 11. 12. Paso 2 Después de que termines el Capítulo 8 • Relee cada enunciado y escribe A o D en la última columna. • Compara la última columna con la primera. ¿Cambiaste de opinión sobre alguno de los enunciados? • En los casos en que hayas estado en desacuerdo con el enunciado, escribe en una hoja aparte un ejemplo de por qué no estás de acuerdo. Capítulo 8 4 Precálculo de Glencoe Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 7. horizontal. Para sumar algebraicamente dos vectores, se suman todos los números del primer vector y luego se suman todos los números del segundo vector. Algunas veces se usan razones trigonométricas para trabajar con vectores. El producto punto (o producto escalar) de dos vectores es un escalar. Los vectores permiten representar fuerzas en un espacio tridimensional. Para calcular el par de torsión se usa el producto punto (o producto escalar). El área de un paralelogramo se puede calcular utilizando el producto punto. NAME DATE 8-1 PERIOD Study Guide and Intervention Introduction to Vectors Geometric Vectors A vector is a quantity that has both magnitude and direction. The magnitude of a vector is the length of a directed line segment, and the direction of a vector is the directed angle between the positive x-axis and the vector. When adding or subtracting vectors, you can use the parallelogram or triangle method to find the resultant. a. v = 60 pounds of force at 125° to the horizontal b. w = 55 miles per hour at a bearing of S45°E Using a scale of 1 cm.: 20 mi/h, draw and label a 55 ÷ 20 or 2.75-centimeter arrow 45° east of south. Using a scale of 1 cm: 20 lb, draw and label a 60 ÷ 20 or 3-centimeter arrow in standard position at a 125° angle to the x-axis. / Z 1 cm: 20 mi/h 0 W 8 & 45° X 125° Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 1 cm: 20 lb 0 Y 4 Exercises Use a ruler and a protractor to draw an arrow diagram for each quantity described. Include a scale on each diagram. 1. r = 30 meters at a bearing of N45°W 2. t = 150 yards at 40° to the horizontal Find the resultant of each pair of vectors using either the triangle or parallelogram method. State the magnitude of the resultant in centimeters and its direction relative to the horizontal. 3. 4. F B G C Chapter 8 5 Glencoe Precalculus Lesson 8-1 Example Use a ruler and a protractor to draw an arrow diagram for each quantity described. Include a scale on each diagram. NAME DATE 8-1 Study Guide and Intervention PERIOD (continued) Introduction to Vectors Vector Applications Vectors can be resolved into horizontal and vertical components. Example Suppose Jamal pulls on the ends of a rope tied to a dinghy with a force of 50 Newtons at an angle of 60° with the horizontal. a. Draw a diagram that shows the resolution of the force Jamal exerts into its rectangular components. Jamal’s pull can be resolved into a horizontal pull x forward and a vertical pull y upward as shown. 50 N y 60° x b. Find the magnitudes of the horizontal and vertical components of the force. The horizontal and vertical components of the force form a right triangle. Use the sine or cosine ratios to find the magnitude of each force. ⎪x⎥ cos 60° = − 50 Right triangle definitions of cosine and sine ⎪y⎥ sin 60° = − 50 ⎪x⎥ = 50 cos 60° Solve for x and y. ⎪y⎥ = 50 sin 60° ⎪x⎥ = 25 Use a calculator. ⎪y⎥ ≈ 43.3 Exercises Draw a diagram that shows the resolution of each vector into its rectangular components. Then find the magnitudes of the vector’s horizontal and vertical components. 1. 7 inches at a bearing of 120° from the horizontal 2. 2.5 centimeters per hour at a bearing of N50°W 3. YARDWORK Nadia is pulling a tarp along level ground with a force of 25 pounds directed along the tarp. If the tarp makes an angle of 50° with the ground, find the horizontal and vertical components of the force. What is the magnitude and direction of the resultant? 4. TRANSPORTATION A helicopter is moving 15° north of east with a velocity of 52 km/h. If a 30-kilometer per hour wind is blowing from a bearing of 250°, find the helicopter’s resulting velocity and direction. Chapter 8 6 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. The magnitude of the horizontal component is about 25 Newtons, and the magnitude of the vertical component is about 43 Newtons. NAME 8-1 DATE PERIOD Practice Introduction to Vectors Use a ruler and a protractor to draw an arrow diagram for each quantity described. Include a scale on each diagram. 2. t = 100 pounds of force at 60° to the horizontal Lesson 8-1 1. r = 60 meters at a bearing of N45°E Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 3. GROCERY SHOPPING Caroline walks 45° north of west for 1000 feet and then walks 200 feet due north to go grocery shopping. How far and at what north of west quadrant bearing is Caroline from her apartment? 4. CONSTRUCTION Roland is pulling a crate of construction materials with a force of 60 Newtons at an angle of 42° with the horizontal. a. Draw a diagram that shows the resolution of the force Roland exerts into its rectangular components. b. Find the magnitudes of the horizontal and vertical components of the force. 5. AVIATION An airplane is flying with an airspeed of 500 miles per hour on a heading due north. If a 50-mile per hour wind is blowing at a bearing of 270°, determine the velocity and direction of the plane relative to the ground. Chapter 8 7 Glencoe Precalculus NAME 8-1 DATE PERIOD Word Problem Practice Introduction to Vectors 1. SAILING A captain sails a boat east for 200 kilometers at a bearing of 150°. Use a ruler and protractor to draw an arrow diagram for the quantities described. Include a scale on the diagram. 3. CANOEING A person in a canoe wants to cross a 65-foot-wide river. He begins to paddle straight across the river at 1.2 m/s while a current is flowing perpendicular to the canoe. If the resulting velocity of the canoe is 3.2 m/s, what is the speed of the current to the nearest tenth? 4. TRAVEL Karrie is pulling her luggage across the airport floor. She applies a 22-newton force to the handle of the bag when the bag makes a 72-degree angle with the floor. What is the magnitude of the force that moves the luggage straight forward? What effect would it have if Karrie moved the handle closer to the floor, decreasing the angle? 2. FARMING Two tractors are removing a tree stump as shown. One tractor pulls with a force of 2000 newtons, and the other tractor pulls with a force of 1500 newtons. The angle between the two tractors is 40°. 1500 N 20° 20° a. What is the sum of the horizontal components of the tractors? What is the sum of the vertical components? 6. SKATEBOARDING Meredith is skateboarding along a path 20° north of east for 35 meters. She then changes paths and travels for 45 meters along a path 30° north of east. b. What is the resulting force on the tree stump? a. Use a ruler and protractor to draw an arrow diagram representing the situation. c. Would changing the angle of the tractors affect the magnitude of the resulting force if the angle between the tractors remained 40°? Explain. b. Find the resulting distance and the direction of her path. Chapter 8 8 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 5. ORIENTEERING In an orienteering competition, Jada walks N70°W for 200 meters. She then walks due east for 90 meters. How far and at what bearing is Jada from her starting point? 2000 N NAME DATE 8-1 PERIOD Enrichment More Than Two Forces Acting on an Object Example CONSTRUCTION Kendra is pulling on a box with a force of 80 newtons at an angle of 70° with the ground at the same time that Kyle is pulling on the box with a force of 100 newtons at an angle of 150° with the ground. A third force of 120 N acts at an angle of 180°. Find the magnitude and direction of the resultant force acting on the box. 80 N 100 N 120 N 180° 150° 70° First, add two of the vectors. The order in which the vectors are added does not matter. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Add the 80 N vector and the 100 N vector first. Now add the resulting vector to the 120 N vector. 100 N a r a 80 N 120 N The resultant force is 219 N at a direction of 145°. Find the magnitude and direction of the resultant force acting on each object. 1. DOGS Three dogs are pulling a wagon. One dog acts with 40 N at 50° on the wagon. The second dog acts with 100 N at 110°. The third dog acts with 10 N at 150°. Find the magnitude and direction of the resultant force. 2. MOVING Three men are trying to move a sofa. One man is pushing on the sofa with a force of 40 N at an angle of 50° with the ground. A second man exerts a force of 100 N at 110°, and a third man exerts a force of 10 N at 150°. Find the magnitude and direction of the resultant force. Chapter 8 9 Glencoe Precalculus Lesson 8-1 Three or more forces may work on an object at one time. Each of these forces can be represented by a vector. To find the resultant vector that acts upon the object, you can add the individual vectors two at a time. NAME DATE 8-2 PERIOD Study Guide and Intervention Vectors in the Coordinate Plane Vectors in the Corrdinate Plane The magnitude of a vector in the coordinate plane is found using the Distance Formula. Example 1 ⎯⎯⎯ with initial point X(2, −3) and Find the magnitude of XY terminal point Y(-4, 2). ⎯⎯⎯ using the Distance Formula. Determine the magnitude of XY ⎪XY ⎯⎯⎯⎥ = √(x - x1)2 + (y2 - y1)2 2 = 4 - 2) + [2 - (-3)] √(-4 2 2 Y y 2 (-6) 2 + 5 2 = √ x 0 −4 −2 or about 7.8 units = √61 Example 2 4 −2 −4 ⎯⎯⎯as an ordered pair. Represent XY ⎯⎯⎯ = 〈x2 - x1, y2 - y1〉 XY = 〈-4 - 2, 2 - (-3)〉 = 〈-6, 5〉 2 X Component form (x1, y1) = (2, −3) and (x2, y2) = (−4, 2) Subtract. Find each of the following for s = 〈4, 2〉 and t = 〈-1, 3〉. s + t = 〈4, 2〉 + 〈-1, 3〉 = 〈4 + (-1), 2 + 3〉 or 〈3, 5〉 Substitute. Vector addition b. 3s + t 3s + t = 3〈4, 2〉 + 〈-1, 3〉 Substitute. = 〈12, 6〉 + 〈-1, 3〉 Scalar multiplication = 〈11, 9〉 Vector addition Exercises ⎯⎯⎯ with the Find the component form and magnitude of the vector AB given initial and terminal points. 1. A(12, 41), B(52, 33) 2. A(-15, 0), B(7, -19) Find each of the following for f = 〈4, -2〉, g = 〈24, 21〉, and h = 〈-1, -3〉. 3. f - g 4. 8g - 2f + 3h 5. 2g + h 6. f - 2(g + 2h) Chapter 8 10 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. a. s + t NAME DATE 8-2 Study Guide and Intervention PERIOD (continued) Vectors in the Coordinate Plane Unit Vectors A vector that has a magnitude of 1 unit is called a unit vector. A unit vector in the direction of the positive x-axis is denoted as i = 〈1, 0〉, and a unit vector in the direction of the positive y-axis is denoted as j = 〈0, 1〉. Vectors can be written as linear combinations of unit vectors by first writing the vector as an ordered pair and then writing it as a sum of the vectors i and j. Example 1 Find a unit vector u with the same direction as v = 〈-4, -1〉. 1 u=− v Unit vector with the same direction as v 1 = − 〈-4, -1〉 ⎪〈-4, -1〉⎥ Substitute. 1 = − 〈-4, -1〉 √ (-4)2 + (-1)2 a2 + b2 ⎪〈a, b〉⎥ = √ 1 =− 〈-4, -1〉 Simplify. √ 17 〈 -4 17 - 17 −, −〉 〈 〉 17 17 17 -1 -4 = − ,− or √ 17 √ √ √ Scalar multiplication Example 2 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. ⎯⎯⎯ be the vector with initial point M(2, 2) and terminal Let MP ⎯⎯⎯ as a linear combination of the vectors i and j. point P(5, 4). Write MP ⎯⎯⎯⎯ . First, find the component form of MP ⎯⎯⎯⎯ = 〈x2 - x1, y2 - y1〉 MP Component form = 〈5 - 2, 4 - 2〉 or 〈3, 2〉 (x1, y1) = (2, 2) and (x2, y2) = (5, 4) Then rewrite the vector as a linear combination of the standard unit vectors. ⎯⎯⎯⎯ = 〈3, 2〉 MP = 3i + 2j Component form 〈a, b〉 = ai + bj Exercises Find a unit vector u with the same direction as the given vector. 1. p = 〈4, -3〉 2. w = 〈10, 25〉 ⎯⎯⎯⎯ be the vector with the given initial and terminal points. Write MN ⎯⎯⎯⎯ Let MN as a linear combination of the vectors i and j. 3. M(2, 8), N(-5, -3) 4. M(0, 6), N(18, 4) Find the component form of v with the given magnitude and direction angle. 5. |v| = 18, θ = 240° 6. |v| = 5, θ = 95° Find the direction angle of each vector to the nearest tenth. 7. -4i + 2j Chapter 8 8. 〈2, 17〉 11 Glencoe Precalculus Lesson 8-2 ⎪ v⎥ NAME 8-2 DATE PERIOD Practice Vectors in the Coordinate Plane ⎯⎯⎯ with the given initial and Find the component form and magnitude of AB terminal points. 1. A(2, 4), B(-1, 3) 2. A(4, -2), B(5, -5) 3. A(-3, -6), B(8, -1) Find each of the following for v = 〈2, -1〉 and w = 〈-3, 5〉. 4. 3v 5. w - 2v 6. 4v + 3w 7. 5w - 3v Find a unit vector u with the same direction as v. 8. v = 〈-3, 6〉 9. v = 〈-8, -2〉 10. D(4, -5), E(6, -7) 11. D(-4, 3), E(5, -2) 12. D(4, 6), E(-5, -2) 13. D(2, 1), E(3, 7) Find the component form of v with the given magnitude and direction angle. 14. |v| = 12, θ = 42° 15. |v| = 8, θ = 132° 16. GARDENING Anne and Henry are lifting a stone statue and moving it to a new location in their garden. Anne is pushing the statue with a force of 120 newtons at a 60° angle with the horizontal while Henry is pulling the statue with a force of 180 newtons at a 40° angle with the horizontal. What is the magnitude of the combined force they exert on the statue? Chapter 8 12 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. ⎯⎯⎯ be the vector with the given initial and terminal points. Write DE ⎯⎯⎯ Let DE as a linear combination of the vectors i and j. NAME 8-2 DATE PERIOD Word Problem Practice Vectors in the Coordinate Plane 1. TRACK Monica is throwing the javelin in a track meet. While running at 4 meters per second, she throws the javelin with a velocity of 28 meters per second at an angle of 48°. 4. AIRPLANES An airplane is traveling 300 kilometers per hour due east. A wind is blowing 35 kilometers per hour 75° south of west. What is the resulting speed of the airplane? a. What is the resultant speed of the javelin? 6. KAYAKING Walter is kayaking across a river that has a current of 2.5 meters per second. He is paddling at a rate of 4 meters per second perpendicular to the shore. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. b. What is the resultant direction of the javelin? end 2.5 m/s 2. TRANSPORTATION Jordyn is riding the bus to school. The bus travels north for 4.5 miles, east for 2 miles, and then 30° north of east for 1.5 miles. Express Jordyn’s commute as a linear combination of unit vectors i and j. 4 m/s θ start a. What is the resultant velocity of the kayak? b. At what angle will Walter be moving with respect to the shore? 3. HIKING Amel is hiking in the forest. He hikes 2 miles west and then hikes 3.4 miles north. If he would have hiked diagonally to reach the same ending point, how much shorter would his hike have been? Chapter 8 c. If Walter wants to land directly in front of his starting point, at what angle with respect to the shore should he kayak? 13 Glencoe Precalculus Lesson 8-2 5. FLYING To reach a destination, a pilot is plotting a course that will result in a velocity of 450 miles per hour at an angle of 30° north of west. The wind is blowing 50 miles per hour to the north. Find the direction and speed the pilot should set to achieve the desired resultant. 48° NAME DATE 8-2 PERIOD Enrichment Friction and the Normal Force According to Newton’s first law of motion, if an object is moving with constant velocity, then all the forces in the system are balanced. If the object is not moving at a constant velocity, then the forces are unbalanced. So, if a person is pushing on an object and the object is moving at a constant velocity, the force of the person pushing on the object is balanced by the force of friction. The coefficient of friction μ (pronounced “mu”) is the ratio of the force of friction between two surfaces and the force pushing the surfaces together. When an object is resting on the ground, the force pushing them together is found by multiplying the mass (in kilograms) by acceleration due to gravity, -9.8 m/s2. The normal force n is the force of the ground pushing back up on the object. Example Consider a person pulling a 7-kilogram wagon with a constant velocity as shown in the diagram. The person is pulling with a force of 25 newtons and the wagon handle makes a 40° angle with the horizontal. What is the coefficient of friction for the situation? 25 N 40° 25 N 16.1 N 52.5 N 40° -19.2 N 19.2 N -68.6 N x = 25 cos 40° y = 25 sin 40° ≈ 19.2 x-component ≈ 16.1 y-component Force due to gravity = mass × acceleration due to gravity 7(-9.8) = -68.6 n = 68.6 - 16.1 = 52.5 Normal force 19.2 μ = − about 0.37 Coefficient of friction 52.5 Therefore, the coefficient of friction is 0.37. Exercises 1. What is the coefficient of friction for a person pulling a 41-kilogram child on a sled if the angle of the rope is 45° and the force of the pull is 50 newtons? 2. What is the coefficient of friction for a person pushing a 25-kilogram box across a carpeted floor with a force of 75 newtons if the force is being applied at 25°? Chapter 8 14 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. A force diagram can be used to represent this situation. Calculate the x-component and the y-component of the 25-newton force. Because the wagon is moving at a constant velocity, the force of friction has to be equal to, but opposite the x-component. The force of gravity is balanced by the sum of the y-component and the normal force. NAME DATE 8-3 PERIOD Study Guide and Intervention Dot Products and Vector Projections Dot Product The dot product of a = 〈a 1, a 2〉 and b = 〈b 1, b 2〉 is defined as a · b = a 1b 1 + a 2b 2. The vectors a and b are orthogonal if and only if a · b = 0. a·b If θ is the angle between nonzero vectors a and b, then cos θ = − . |a| |b| Find the dot product of u and v. Then determine if u and v Example 1 are orthogonal. a. u = 〈5, 1〉, v = 〈-3, 15〉 u · v = 5(−3) + 1(15) =0 Since u · v = 0, u and v are orthogonal. Example 2 b. u = 〈4, 5〉, v = 〈8, -6〉 u · v = 4(8) + 5(-6) =2 Since u · v ≠ 0, u and v are not orthogonal. Find the angle θ between vectors u and v if u = 〈5, 1〉 and v = 〈−2, 3〉. u·v cos θ = − Angle between two vectors 〈5, 1〉 · 〈-2, 3〉 |〈5, 1〉| |〈-2, 3〉| cos θ = − u = 〈5, 1〉 and v = 〈−2, 3〉 -10 + 3 cos θ = − Evaluate. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. √ 26 √ 13 -10 + 3 √ 26 √ 13 θ = cos −1 − or about 112° Simplify and solve for θ. Lesson 8-3 |u| |v| The measure of the angle between u and v is about 112°. Exercises Find the dot product of u and v. Then determine if u and v are orthogonal. 1. u = 〈2, 4〉, v = 〈−12, 6〉 2. u = -8i + 5j, v = 3i −6j Use the dot product to find the magnitude of the given vector. 3. a = 〈9, 3〉 4. c = 〈−12, 4〉 Find the angle θ between u and v to the nearest tenth of a degree. 5. u = 〈-3, -5〉, v = 〈7, 12〉 Chapter 8 6. u = 13i - 5j, v = 6i + 2j 15 Glencoe Precalculus NAME DATE 8-3 PERIOD Study Guide and Intervention (continued) Dot Products and Vector Projections Vector Projection A vector projection is the decomposition of a vector u into two perpendicular parts, w1 and w2, in which one of the parts is parallel to another vector v. When you find the projection of u onto v, you are finding a component of u that is parallel to v. To find the projection of u onto v, use the formula: u·v proj v u = − v. 2 ( |v| ) Example Find the projection of u = 〈8, 6〉 onto v = 〈2, −3〉. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. Step 1 Find the projection of u onto v. Step 2 Find u − proj v u. 〈 108 72 ,− = 〈− 13 13 〉 4 6 = 〈8, 6〉 − - − ,− u·v proj v u = − v |v| 2 ) ( 〈8, 6〉 · 〈2, -3〉 13 13 〉 = − 〈2, -3〉 2 |〈2, -3〉| 〈 〉 2 4 6 〈2, -3〉 or - − ,− = -− 13 〈 〉 13 13 〈 〉 〈 13 〉 108 72 4 6 4 6 ,− . , − and u = - − ,− + − Therefore, proj v u is - − 13 13 13 13 13 Find the projection of u onto v. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. 1. u = 〈3, 2〉, v = 〈-4, 1〉 2. u = 〈−7, 3〉, v = 〈8, 5〉 3. u = 〈1, 1〉, v = 〈9, -7〉 4. u = 7i - 9j, v = 12i + j 5. u = −8i + 2j, v = 6i + 13j Chapter 8 16 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Exercises NAME 8-3 DATE PERIOD Practice Dot Products and Vector Projections Find the dot product of u and v. Then determine if u and v are orthogonal. 1. u = 〈3, 6〉, v = 〈−4, 2〉 2. u = -i + 4j, v = 3i − 2j 3. u = 〈2, 0〉, v = 〈−1, −1〉 Find the angle θ between u and v to the nearest tenth of a degree. 4. u = 〈−1, 9〉, v = 〈3, 12〉 5. u = 〈−6, −2〉, v = 〈2, 12〉 6. u = 27i + 14j, v = i − 7j 7. u = 5i − 4j, v = 2i + j 8. u = 〈4, 8〉, v = 〈−1, 2〉 Lesson 8-3 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Find the projection of u onto v. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. 9. u = 〈62, 21〉, v = 〈−12, 4〉 10. u = 〈−2, −1〉, v = 〈−3, 4〉 11. TRANSPORTATION Train A and Train B depart from the same station. The path that train A takes can be represented by 〈33, 12〉. If the path that train B takes can be represented by 〈55, 4〉, find the angle between the pair of vectors. 12. PHYSICS Janna is using a force of 100 pounds to push a cart up a ramp. The ramp is 6 feet long and is at a 30° angle with the horizontal. How much work is Janna doing in the vertical direction? (Hint: Use the sine ratio and the formula W = F · d.) Chapter 8 17 Glencoe Precalculus NAME 8-3 DATE PERIOD Word Problem Practice Dot Products and Vector Projections 1. SUBMARINES The path of a submarine can be described by the vector v = 〈8, 3〉. If the submarine then changes direction and travels along the vector u = 〈2, 5〉, what is the distance traveled by the submarine? 4. TRAVELING A pilot is carrying a bag weighing 150 newtons up a flight of stairs. The staircase covers a horizontal distance of 8 meters and a vertical distance 7.5 meters. a. What is the length of the staircase? 2. TARGETS Two clay pigeons are thrown at the same time. If the path of the clay pigeons can be represented by the vectors p = 〈42, 58〉 and c = 〈59, 73〉, what was the measure of the angle between the clay pigeons? b. What is the measure of the angle made by the staircase? c. How much work is done by the pilot? 3. BOATING Shea is pulling a boat along a dock using a rope. She exerts a force of 200 newtons on the rope and pulls the boat 10 meters. a. Determine the amount of work done if the angle of the rope is at 40° with the horizontal; 90° with the horizontal. 60° 6. SCAVENGER HUNT During a scavenger hunt, Alexis and Marty go in different directions. If the path that Alexis takes can be represented by 〈9, 18〉 and the path taken by Marty can be represented by 〈-15, 12〉, who travels the farthest distance? b. Use your results from part a to explain why as the angle increases the work decreases. Chapter 8 18 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 5. CARNIVALS A slide at a carnival has an incline of 60°. A 50-pound girl gets part way down the slide and stops. Ignoring the force of friction, what is the magnitude of the force that is required to keep her from sliding down farther? NAME DATE 8-3 PERIOD Enrichment Vector Equations Let a, b, and c be fixed vectors. The equation f(x) = a - 2xb + x 2c defines a vector function of x. For the values of x shown, the assigned vectors are given below. x f(x) -2 -1 0 1 2 a + 4b + 4c a + 2b + c a a - 2b + c a - 4b + 4c If a = 〈0, 1〉, b = 〈1, 1〉, and c = 〈2, –2〉, the resulting vectors for the values of x are as follows. x f(x) -2 -1 0 1 2 〈12, -3〉 〈4, 1〉 〈0, 1〉 〈0, -3〉 〈4, -11〉 For each of the following, complete the table of resulting vectors. 1. f(x) = x 3a - 2x 2b + 3xc a = 〈1, 1〉 b = 〈2, 3〉 x –1 c = 〈3, –1〉 f(x) 0 1 2. f(x) = 2x 2a + 3xb - 5c a = 〈0, 1, 1〉 b = 〈1, 0, 1〉 x –2 c = 〈1, 1, 0〉 f(x) Lesson 8-3 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 2 –1 0 1 3. f(x) = x 2c + 3xa - 4b a = 〈1, 1, 1〉 b = 〈3, 2, 1〉 x 0 c = 〈0, 1, 2〉 f(x) 1 2 3 4. f(x) = x 3a - xb + 3c a = 〈0, 1, –2〉 b = 〈1, –2, 0〉 c = 〈-2, 0, 1〉 x 0 f(x) 1 2 3 Chapter 8 19 Glencoe Precalculus NAME DATE 8-4 PERIOD Study Guide and Intervention Vectors in Three-Dimensional Space Coordinates in Three Dimensions Ordered triples, like ordered pairs, can be used to represent vectors. Operations on vectors represented by ordered triples are similar to those on vectors represented by ordered pairs. Example HIKING The location of two hikers are represented by the coordinates (10, 2, -5) and (7, -9, 3), where the coordinates are given in kilometers. a. How far apart are the hikers? Use the Distance Formula for points in space. AB = (x2 - x1)2 + (y2 - y1)2 + (z2 - z1)2 √ Distance Formula = √ (7 - 10)2 + ((-9) - 2)2 + (3 - (-5))2 ≈ 13.93 The hikers are about 14 kilometers apart. (x1, y1, z1) = (10, 2, -5) and (x2, y2, z2) = (7, -9, 3) b. The hikers decided to meet at the midpoint between their paths. What are the coordinates of the midpoint? Use the Midpoint Formula for points in space. x +x y +y z +z 10 + 7 2 + (-9) -5 + 3 , −, − ) = ( −, −, − ) (− 2 2 2 2 2 2 1 2 1 2 1 2 (x1, y1, z1) = (10, 2, -5) and (x2, y2, z2) = (7, -9, 3) ≈ (8.5, -3.5, -1) Exercises Plot each point in a three-dimensional coordinate system. 1. (3, 2, 1) 2. (4, −2, -1) z 0 z y 0 y x x Find the length and midpoint of the segment with the given endpoints. 3. (8, -3, 9), (2, 8, -4) 4. (-6, -12, -8), (7, -2, -11) Chapter 8 20 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. The midpoint is at the coordinates (8.5, -3.5, -1). NAME DATE 8-4 PERIOD Study Guide and Intervention (continued) Vectors in Three-Dimensional Space Vectors in Space Operations on vectors represented by ordered triples are similar to those on vectors represented by ordered pairs. Three-dimensional vectors can be added, subtracted, and multiplied by a scalar in the same ways. In space, a vector v in standard position with a terminal point located at (v1, v2, v3) is denoted by 〈v1, v2, v3〉. Thus, the zero vector is 0 = 〈0, 0, 0〉 and the standard unit vectors are i = 〈1, 0, 0〉, j = 〈0, 1, 0〉, and k = 〈0, 0, 1〉. The component form of v can be expressed as a linear combination of these unit vectors, 〈v1, v2, v3〉 = v1i + v2 j + v3k. Example ⎯⎯⎯ with initial Find the component form and magnitude of AB point A(-3, 5, 1) and terminal point B(3, 2, -4). Then find a unit vector in the ⎯⎯⎯. direction of AB ⎯⎯⎯⎯ = 〈x2 - x1, y2 - y1, z2 - z1〉 AB Component form of vector = 〈3 - (-3), 2 - 5, -4 - 1〉 or 〈6, -3, -5〉 (x1, y1, z1) = (-3, 5, 1) and (x2, y2, z2) = (3, 2, −4) ⎯⎯⎯⎯ is Using the component form, the magnitude of AB ⎪AB . ⎯⎯⎯⎯⎥ = √ 62 + (-3)2 + (-5)2 or √70 ⎯⎯⎯ AB = 〈6, -3, -5〉 Using this magnitude and component form, find a ⎯⎯⎯⎯. unit vector u in the direction of AB ⎯⎯⎯⎯ AB u=− Unit vector in the direction of ⎯⎯⎯ AB ⎪AB ⎯⎯⎯⎯⎥ √ 70 3 70 3 70 70 , - −, - − 〉 〈− 35 70 14 √ √ √ ⎯⎯⎯ AB = 〈6, -3, -5〉 and ⎪ ⎯⎯⎯ AB ⎥ = √ 70 Exercises ⎯⎯⎯ with the given initial Find the component form and magnitude of AB ⎯⎯⎯. and terminal points. Then find a unit vector in the direction of AB 1. A(-10, 3, 9), B(8, -7, 3) 2. A(-1, -4, -7), B(8, 4, 10) Lesson 8-4 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 〈6, -3, -5〉 = − or Find each of the following for x = 3i + 2j - 5k, y = i - 5j + 7k, and z = -2i + 12j + 4k. 3. 3x + 2y - 4z Chapter 8 4. -6y + 2z 21 Glencoe Precalculus NAME DATE 8-4 PERIOD Practice Vectors in Three-Dimensional Space Plot each point in a three-dimensional coordinate system. 1. (-3, 4, -1) 2. (2, 0, -5) z 0 y z y 0 x x Locate and graph each vector in space. 3. 〈4, 7, 6〉 4. 〈4, -2, 6〉 z z y y x x 5. A(2, 1, 3), B(-4, 5, 7) 6. A(4, 0, 6), B(7, 1, -3) 7. A(-4, 5, 8), B(7, 2, -9) 8. A(6, 8, -5), B(7, -3, 12) Find the length and midpoint of the segment with the given endpoints. 9. (3, 4, -9), (-4, 7, 1) 10. (-17, -3, 2), (3, -9, 5) Find each of the following for v = 〈2, -4, 5〉 and w = 〈6, -8, 9〉. 11. v + w 12. 5v - 2w 13. PHYSICS Suppose that the force acting on an object can be expressed by the vector 〈85, 35, 110〉, where each measure in the ordered triple represents the force in pounds. What is the magnitude of this force? Chapter 8 22 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. ⎯⎯⎯⎯ with the given initial Find the component form and magnitude of AB ⎯⎯⎯⎯. and terminal points. Then find a unit vector in the direction of AB NAME DATE 8-4 PERIOD Word Problem Practice Vectors in Three-Dimensional Space 1. TRAVELING A family from Des Moines, Iowa, is driving to Tampa, Florida. According to the car’s GPS, Des Moines is at (93.65˚, 41.53˚, 955 ft) and Tampa is at (82.53˚, 27.97˚, 19.7 ft). Determine the longitude, latitude, and altitude of the halfway point. 3. AIRPLANE Safety regulations require airplanes to be at least a half mile apart when they are in the air. Two airplanes near an airport can be represented by the points (300, 455, 2800) and (-250, 400, 5000), where the coordinates are given in feet. a. How far apart are the planes? 2. FARMING A farmer is using a bale elevator to move bales of hay into the loft of his barn. The opening of the loft door is 18 feet away from where the bales will be loaded onto the bale elevator, 3 feet to the right of where the bales will be loaded, and 24 feet above the ground. The opening can be represented by the point (18, 3, 24). The bales will be loaded onto the elevator 3 feet above the ground. This can be represented by (0, 0, 3). b. Are they in violation of the regulation? 4. ROBOTICS An underwater robot is being used to explore parts of the ocean floor. The robot is diving due north at 3 m/s at an angle of 65˚ with the surface of the water. If the current is flowing at 5 m/s at an angle of 20˚ north of west, what is the vector that represents the resultant velocity of the underwater robot? Let i point east, j point north, and k point up. 24 ft 3 ft 3 ft 18 ft 5. ZIP-LINES A resort in Colorado has a series of zip-lines that tourists can take to travel through some wooded areas. The platform of the first zip-line is represented by the point (1.5, 0.5, 0.4) and a second platform can be represented by the point (1.8, 1, 0.2). How long is the zip-line if the coordinates are in miles? a. To the nearest foot, how long should the bale elevator be in order to reach the opening? b. If the bale elevator needs to be 2 feet past the opening, to the nearest foot, how long does the bale elevator have to be? c. If the bale elevator is only 27 feet long and the only thing that can be changed is the 18 feet that the farmer is away from the opening, to the nearest foot, how close does he need to be in order to still have two feet past the opening? Chapter 8 6. BIKING A youth group is hosting a team bike race with pairs of competitors. Each team will switch riders half-way through the race. If the starting point can be represented by (0, 0, 3) and the ending point can be represented by the point (2, -1, 9), at what point will the cyclists trade? 23 Glencoe Precalculus Lesson 8-4 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 2 ft NAME 8-4 DATE PERIOD Enrichment Basis Vectors in Three-Dimensional Space The expression v = ru + sw + tz, is the sum of three vectors each multiplied by a scalar, and is called a linear combination of the vectors u, w, and z. Every vector v ∈ v3 can be written as a linear combination of any three nonparallel vectors. The three nonparallel vectors, which must be linearly independent, are said to form a basis for v3, which contains all vectors having 1 column and 3 rows. Example Write the vector v = 〈-1, -4, 3〉 as a linear combination of the vectors u = 〈1, 3, 1〉, w = 〈1, -2, 1〉, and z = 〈-1, -1, 1〉. r+s-t 〈-1, -4, 3〉 = r 〈1, 3, 1〉 + s 〈1, -2, 1〉 + t 〈-1, -1, 1〉 = 3r - 2s - t r+s+t ( ) -1 = r + s - t -4 = 3r - 2s - t 3=r+s+t Solving the system of equations yields the solution r = 0, s = 1, and t = 2. So, v = w + 2z. 1. v = 〈-6, -2, 2〉, u = 〈1, 1, 0〉, w = 〈1, 0, 1〉, and z = 〈0, 1, 1〉 2. v = 〈5, -2, 0〉, u = 〈1, -2, 3〉, w = 〈-1, 0, 1〉, and z = 〈4, 2, -1〉 3. v = 〈1, -1, 2〉, u = 〈1, 2, -1〉, w = 〈2, 2, 1〉, and z = 〈1, 0, 1〉 Chapter 8 24 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Write each vector as a linear combination of the vectors u, w, and z. NAME 8-4 DATE PERIOD Graphing Calculator Activity Vector Transformations with Matrices Vectors can be used to translate figures in space, and matrix multiplication can be used to transform figures in space. A vertex matrix is a matrix whose columns are the coordinates of the vertices of the figure with the x-coordinate represented by the first row, the y-coordinate represented by the second row, and the z-coordinate represented by the third row. Consider the pyramid shown at the right. z Use the coordinates of the vertices of the pyramid to create a vertex matrix. & A(-2, -2, -2) B(2, -2, -2) 0 " % y C(2, 2, -2) # $ D(-2, 2, -2) x E(0, 0, 2) A B C D E x ⎡-2 2 2 -2 0⎤ ⎢ The vertex matrix for the pyramid is y -2 -2 2 2 0 . ⎢ z ⎣-2 -2 -2 -2 2⎦ To reflect the image over the xz-plane, use the transformation matrix B. ⎡ 1 0 0⎤ ⎢ B = 0 -1 0 ⎢ ⎣0 0 1⎦ Enter B into a graphing calculator. To find the reflected image, find BA. Verify that your answer is correct by graphing the coordinates. Exercises 1. Find the reflected pyramid above when you use the transformation matrix B below. Describe the result. ⎡1 0 0⎤ ⎢ B= 0 1 0 ⎢ ⎣0 0 -1⎦ Chapter 8 2. Find the transformation matrix to reflect over the yz-plane. Check your answer by applying it to the pyramid above. 25 Glencoe Precalculus Lesson 8-4 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Enter the vertex matrix into a graphing calculator. NAME DATE 8-5 PERIOD Study Guide and Intervention Dot and Cross Products of Vectors in Space Dot Products in Space The dot product of two vectors in space is an extension of the dot product of two vectors in a plane. Similarly, the dot product of two vectors is a scalar. The dot product of a = 〈a1, a2, a3〉 and b = 〈b1, b2, b3〉 is defined as a · b = a1b1 + a2b2 + a3b3. The vectors a and b are orthogonal if and only if a · b = 0. As with vectors in a plane, if θ is the angle between nonzero vectors a and b, then a·b cos θ = − . ⎪a⎥ ⎪b⎥ Example 1 Find the dot product of u and v. Then determine if u and v are orthogonal. b. u = 〈3, −2, 1〉, v = 〈4, 5, −1〉 a. u = 〈-3, 1, 0〉, v = 〈2, 6, 4〉 u · v = u1v1 + u2v2 + u3v3 u · v = u1v1 + u2v2 + u3v3 = 3(4) + (−2)(5) + 1(−1) = −3(2) + 1(6) + 0(4) = 12 + (−10) -1 or 1 = −6 + 6 + 0 or 0 Since u · v ≠ 0, u and v are not orthogonal. Since u · v = 0, u and v are orthogonal. Example 2 Find the angle θ between vectors u and v if u = 〈4, 8, -3〉 and v = 〈9, −3, 0〉. u·v cos θ = − Angle between two vectors ⎪u⎥ ⎪v⎥ u = 〈4, 8, -3〉 and v = 〈9, -3, 0〉 12 cos θ = − Evaluate the dot product and magnitude. √ 89 √ 90 12 θ = cos -1 − or about 82.3° 89.5 Simplify and solve for θ. The measure of the angle between u and v is about 82.3°. Exercises Find the dot product of u and v. Then determine if u and v are orthogonal. 1. u = 〈3, -2, 9〉, v = 〈1, 2, 4〉 2. u = 〈-2, -4, -6〉, v = 〈-3, 7, -4〉 3. u = 〈4, -3, 8〉, v = 〈2, -2, -3〉 4. u = 3i + 6j - 3k, v = -5i - 2j - 9k Find the angle θ between vectors u and v to the nearest tenth of a degree. 5. u = 〈5, -22, 9〉, v = 〈14, 2, 4〉 6. u = 〈4, -5, 7〉, v = 〈11, -8, 2〉 7. u = -4i + 5j - 3k, v = -8i - 12j - 9k 8. u = i + 2j - k, v = -i + 4j - 3k Chapter 8 26 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 〈4, 8, -3〉·〈9, -3, 0〉 cos θ = −− ⎪〈4, 8, -3〉⎥ ⎪〈9, -3, 0〉⎥ NAME DATE 8-5 PERIOD Study Guide and Intervention (continued) Dot and Cross Products of Vectors in Space Cross Products Unlike the dot product, the cross product of two vectors is a vector. This vector does not lie in the plane of the given vectors but is perpendicular to the plane containing the two vectors. Cross Product of Vectors in Space If a = a1i + a2j + a3k and b = b1i + b2j + b3k, the cross product of a and b is the vector a × b = (a2b3 - a3b2)i - (a1b3 - a3b1)j + (a1b2 - a2b1)k. If two vectors have the same initial point and form the sides of a parallelogram, the magnitude of the cross product will give you the area of the parallelogram. If three vectors have the same initial point and form adjacent edges of a parallelepiped, then the absolute value of the triple scalar product gives the volume. To find the triple scalar product, use the same matrix set up that is used for cross products, but i, j, and k are replaced by the third vector. Example Find the cross product of u = 〈0, 4, 1〉and v = 〈0, 1, 3〉. Then show that u × v is orthogonal to both u and v. i j k u×v= 0 4 1 u = 0i + 4j + k and v = 0i + j + 3k 0 1 3 0 4 0 1 4 1 = ij+ k Determinant of a 3 × 3 matrix 1 3 0 1 0 3 = (12 - 1)i − (0 - 0) j + (0 − 0)k Determinants of 2 × 2 matrices ⎪ ⎥ = 11i - 0j + 0k Simplify. = 11i or 〈11, 0, 0〉 Component form To show that u × v is orthogonal to both u and v, find the dot product of u × v with u and u × v with v. (u × v) · u (u × v) · v = 〈11, 0, 0〉 · 〈0, 4, 1〉 = 〈11, 0, 0〉 · 〈0, 1, 3〉 = 11(0) + 0(4) + 0(1) = 11(0) + 0(1) + 0(3) =0+0+0 =0+0+0 =0 =0 Because both dot products are zero, the vectors are orthogonal. Exercises Find the cross product of u and v. Then show that u × v is orthogonal to both u and v. 1. u = 〈2, 3, -1〉, v = 〈6, -2, -4〉 Lesson 8-5 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. ⎪ ⎥ ⎪ ⎥ ⎪ ⎥ 2. u = 〈5, 2, 8〉, v = 〈-1, 2, 4〉 Chapter 8 27 Glencoe Precalculus NAME 8-5 DATE PERIOD Practice Dot and Cross Products of Vectors in Space Find the dot product of u and v. Then determine if u and v are orthogonal. 1. 〈-2, 0, 1〉 · 〈3, 2, -3〉 2. 〈-4, -1, 1〉 · 〈1, -3, 4〉 3. 〈0, 0, 1〉 · 〈1, -2, 0〉 Find the angle θ between vectors u and v to the nearest tenth of a degree. 4. u = 〈1, -2, 1〉, v = 〈0, 3, -2〉 5. u = 〈3, -2, 1〉, v = 〈-4, -2, 5〉 6. u = 〈2, -4, 4〉, v = 〈-2, -1, 6〉 Find the cross product of u and v. Then show that u × v is orthogonal to both u and v. 7. 〈1, 3, 4〉 × 〈-1, 0, -1〉 9. 〈3, 1, 2〉 × 〈2, -3, 1〉 8. 〈3, 1, -6〉 × 〈-2, 4, 3〉 10. 〈4, -1, 0〉 × 〈5, -3, -1〉 11. u = 〈9, 4, 2〉, v = 〈6, -4, 2〉 12. u = 〈2, 0, -8〉, v = 〈-3, -8, -5〉 13. Find the volume of the parallelepiped with adjacent edges represented by the vectors 〈3, -2, 9〉, 〈6, -2, -7〉, and 〈-8, -5, -2〉. 14. TOOLS A mechanic applies a force of 35 newtons straight down to a ratchet that is 0.25 meter long. What is the magnitude of the torque when the handle makes a 20° angle above the horizontal? Chapter 8 28 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Find the area of the parallelogram with adjacent sides u and v. NAME 8-5 DATE PERIOD Word Problem Practice Dot and Cross Products of Vectors in Space 1. MECHANIC A mechanic is setting the timing of an engine. He is using a ratchet to turn the crankshaft. The ratchet is 0.5 meter long and the mechanic applies 22 newtons of force straight down on the handle when the handle is at a 25° angle with the horizontal. What is the magnitude of the torque? 5. BICYCLING A cyclist applies a force straight down on a bicycle pedal, as shown in the diagram. The length to the pedal’s axle is 0.2 meter and the angle created with the vertical is 60°. The magnitude of the torque is 150 newton meters. Find the force applied to the pedal. 60° 9 3. MIRROR Two adjacent edges of a mirror in a dressing room are represented by the vectors 〈3, 4, 2〉 and 〈-4, 4, 3〉. What is the area of the mirror? 6. ROCKETS Two rockets are launched simultaneously. The first rocket starts at the point (0, 1, 0) and after 1 second is at the point (3, 7, 12). The second rocket starts at the point (0, -1, 0) and after 1 second is at the point (3, -8, 10). 4. SCULPTURE A parallelepiped sculpture is being created. When the sculpture is set, three adjacent edges can be represented by the vectors t = 〈15, 12, 10〉, u = 〈13, -8, -5〉, and a. What vector represents the path of the first rocket? v = 〈-9, 13, 12〉. What is the surface area of the sculpture? b. What vector represents the path of the second rocket? c. What is the measure of the angle between the two rockets? d. If the velocity of the rockets remains constant, what vectors would represent the rockets at 3 seconds? Chapter 8 29 Glencoe Precalculus Lesson 8-5 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 2. REVOLVING DOOR Erica is standing in a revolving door that is not moving. If Erica wants to produce just enough torque to make the door rotate but wants to apply the least amount of force, where should she push on the door with respect to the axis of rotation? NAME 8-5 DATE PERIOD Enrichment Linearly Dependent Vectors The zero vector is 〈0, 0〉 in two dimensions and 〈0, 0, 0〉 in three dimensions. A set of vectors is called linearly dependent if and only if there exist scalars, not all zero, such that a linear combination of the vectors yields a zero vector. Example Are the vectors 〈-1, 2, 1〉, 〈1, -1, 2〉, and 〈0, -2, -6〉 linearly dependent? Solve a〈-1, 2, 1〉 + b〈1, -1, 2〉 + c〈0, -2, -6〉 = 〈0, 0, 0〉. -a + b =0 2a - b - 2c = 0 a + 2b - 6c = 0 The above system does not have a unique solution. Any solution must satisfy the conditions that a = b = 2c. 1 Hence, one solution is a = 1, b = 1, and c = − . 2 1 〈-1, 2, 1〉 + 〈1, -1, 2〉 + − 〈0, -2, -6〉 = 〈0, 0, 0〉, so the three vectors are linearly dependent. 2 1. 〈-2, 6〉, 〈1, -3〉 2. 〈3, 6〉, 〈2, 4〉 3. 〈1, 1, 1〉, 〈-1, 0, 1〉, 〈1, -1, -1〉 4. 〈1, 1, 1〉, 〈-1, 0, 1〉, 〈-3, -2, -1〉 5. 〈2, -4, 6〉, 〈3, -1, 2〉, 〈-6, 8, 10〉 9 6. 〈1, -2, 0〉, 〈2, 0, 3〉, -1, 1, − Chapter 8 〈 30 4 〉 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Determine whether the given vectors are linearly dependent. Write yes or no. If yes, give a linear combination that yields a zero vector. NAME DATE 8-5 PERIOD Graphing Calculator Activity Use Matrices to Find the Volume of Parallelepipeds The volume of a parallelepiped with adjacent sides t = 〈t1, t2, t3〉, u = 〈u1, u2, u3〉, and v = 〈v1, v2, v3〉 can be calculated by finding the determinant of the matrix below. ⎡t1 t2 t3 ⎤ ⎢u u u ⎢ 1 2 3 ⎣v1 v2 v3 ⎦ Example Find the volume of a parallelepiped with adjacent sides t = 〈3, -2, 8〉, u = 〈4, 9, -1〉, and v = 〈-1, -5, -7〉. Enter the data into the graphing calculator under matrix A. 2nd 2 [MATRIX] ENTER (–) 7 8 ENTER ENTER 2nd ENTER 4 ENTER 9 3 ENTER ENTER (–) 1 3 ENTER ENTER 3 (–) ENTER 1 ENTER (–) (–) 5 ENTER [QUIT] Now use the MATH menu under MATRIX to calculate the following determinant. [MATRIX] ENTER 2nd [MATRIX] ENTER ) ENTER The determinant is -350. Volume cannot be negative, so the volume is 350 cubic units. Exercises 1. Find the volume of the parallelepiped with adjacent sides t = 〈6, -12, -9〉, u = 〈4, 3, 9〉, and v = 〈2, 3, 1〉. 2. Find the volume of the parallelepiped with adjacent sides t = 〈8, -22, 90〉, u = 〈-31, 3, 22〉, and v = 〈-65, 31, 0〉. 3. The volume of a parallelepiped is 112 cubic units. Three adjacent sides are t = 〈-10, 3, 4〉, u = 〈-8, 7, 3〉, and v = 〈-6, -2, x〉. Is 3, 5, or 9 the correct value of x? Chapter 8 31 Glencoe Precalculus Lesson 8-5 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 2nd NAME DATE 8 PERIOD Chapter 8 Quiz 1 SCORE (Lessons 8-1 and 8-2) 1. The vector v has a magnitude of 13 millimeters and a direction of 84°. Find the magnitude of its vertical and horizontal components. 1. 2. Find a unit vector with the same direction as v = 〈6, -3〉. A 〈−, - −〉 B 〈- −, −〉 C 〈- −, - −〉 D 〈−, - −〉 2 √5 5 √5 2 √5 5 5 √5 5 2 √5 5 √5 5 2 5 1 5 2. 3. 2a - b 3. B C 4. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 4. −a + 2b ⎯⎯⎯⎯ with initial point 5. Find the component form of AB A(1, -3) and terminal point B(-6, -8). 5. ⎯⎯⎯⎯ as a linear combination of the standard unit vectors 6. Write CD for C(7, -4) and D(-8, 1). 6. 7. Two people are carrying a box. One person exerts a force of 140 pounds at an angle of 65.5° with the horizontal. The other person exerts a force of 115 pounds at an angle of 58.3° with the horizontal. Find the net weight of the box. 8. Find each of the following for v = 〈6, -6〉 and w = 〈3, -4〉. b. 2v + 3w a. -5w c. NAME 8 4w - v 7. 8a. 8b. 8c. DATE PERIOD Chapter 8 Quiz 2 SCORE (Lesson 8-3) 1. Maggie is pulling a tarp along level ground with a force of 25 newtons. If the tarp makes an angle of 50° with the ground, what are the vertical and horizontal components of the force? Let a = 〈3, 8〉 and b = 〈-4, 6〉. 2. Which is the dot product of a and b? A 36 B 0 C 〈-1, 14〉 D 〈7, 2〉 1. 2. 3. Find the angle θ between a and b to the nearest tenth. 3. 4. Find the projection of a onto b. 4. 5. SLEDDING A person is pulling a sled with a constant force of 35 newtons. The angle the rope makes with the sled is 40°, and the sled is pulled 20 meters. Find the work done in joules. 5. Chapter 8 Assessment Find the resultant of each pair of vectors using either the triangle or the parallelogram method. State the magnitude in centimeters and its direction relative to the horizontal. 33 Glencoe Precalculus NAME DATE 8 PERIOD Chapter 8 Quiz 3 SCORE (Lesson 8-4) 1. Find the component form and magnitude of a vector with initial point A(3, 4, 10) and terminal point B(8, 4, -2). 1. 2. Find 3x + y - z for x = 〈-1, 5, 2〉, y = 〈2, -3, 4〉, and z = 〈-4, 1, 0〉. 2. 1 3. Find 2v + − w - z for v = 2i - j + 5k, w = -3i + 4j - 6k 3 and z = 3j - 2k. 3. 4. Which is the midpoint between points (3, 9, -2) and (-4, 9, -6)? A (−72 , 0, 2) ( 1 , 9, -4 B (-12, 81, 12) C (-1, 18, -8) D - − 2 ) 4. 5. Find the distance between points A(12, -9, 15) and B(1, 6, 2). 5. NAME PERIOD Chapter 8 Quiz 4 SCORE (Lesson 8-5) 1. Find the dot product of a and b if a = 〈7, -3, 8〉 and b = 〈5, -2, -4〉. Then determine if a and b are orthogonal. 1. 2. Find the cross product of c and d if c = 〈5, -5, 4〉 and d = 〈2, 3, -6〉. Verify that the resulting vector is orthogonal to c and d. 2. 3. Find the measure of the angle between the vectors 〈6, -3, 1〉 and 〈8, 9, -11〉. 3. 4. A 32-newton force is applied straight down on the end of a wrench that is 0.3 meters long. What is the magnitude of the torque when the wrench is at a 35° angle with the horizontal? 4. 5. Find the area of a parallelogram with adjacent sides 〈5, 2, 8〉 and 〈-3, 4, 6〉. A 8.5 units2 Chapter 8 B 17.4 units2 C 35.7 units2 D 63.2 units2 34 5. Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 8 DATE NAME 8 DATE PERIOD Chapter 8 Mid-Chapter Test SCORE Part I Write the letter for the correct answer in the blank at the right of each question. 1. SLEDDING Jordyn pulls a sled with a force of 120 newtons at an angle of 25° with the horizontal. Find the magnitude of the horizontal component of the force. B 56.0 N C 88.3 N D 108.8 N 1. ⎯⎯⎯⎯ be a vector with the given initial point A(8, −4) and terminal point 2. Let AB ⎯⎯⎯⎯ as a linear combination of the vectors i and j. B(−2, −3). Write AB J −6i + 7j 2. 3. Find the component form and magnitude of the vector with initial point A(−6, 4) and terminal point B(−2, −1). A 〈4, -5〉; √41 B 〈4, -5〉; 9 C 〈-4, 5〉; √ 41 D 〈-4, 5〉; 9 3. F 10i - j G 6i - 7j H −10i + j 4. Find the dot product of u = 〈8, 7〉 and v = 〈-3, -2〉. Then determine if u and v are orthogonal. F −9, orthogonal G −9, not orthogonal H −38, not orthogonal J −38, orthogonal 4. 5. If u = 〈-8, 7〉 and v = 〈4, -6〉, find 2u - v. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. A 〈−20, 20〉 B 〈20, −20〉 C 〈−12, 8〉 D 〈12, −8〉 5. Part II 6. Find the projection of u = 〈7, −3〉 onto v = 〈4, 3〉. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. 6. 7. Find the measure of the angle θ between u = 〈9, 9〉 and v = 〈-7, 8〉 to the nearest tenth of a degree. 7. 8. Find the resultant of the pair of vectors using either the triangle or parallelogram method. 8. 9. FOOTBALL With time running out in a game, Rodney runs with the football at a speed of 3.8 meters per second and throws the ball at a speed of 7 meters per second at an angle of 28° to the horizontal. a. Write the component form of the vectors representing Rodney’s velocity and the path of the ball. 9a. b. What is the resultant speed and direction of the ball? 9b. Chapter 8 35 Glencoe Precalculus Assessment A 50.7 N NAME DATE PERIOD 8 Chapter 8 Vocabulary Test SCORE component form opposite vectors terminal point components ordered triple triple scalar cross product orthogonal true bearing direction parallel vectors unit vector dot product quadrant bearing vector initial point resultant z-axis magnitude standard position Choose the best term from the vocabulary list above to complete each sentence. 1. 1. When a vector is in its x and y components, the vector is said to be in . 2. The 2. is the point where the vector begins. 3. Two vectors are equal to zero. 3. if their dot product is 4. 4. The length of a vector is known as its . 5. . 6. A point in space can be represented by a(n) 7. A(n) 8. 6. . 7. is a vector that has a length of one unit. are vectors that have the same magnitude and opposite directions. 9. The ending point of a vector is the 10. A vector is in is at the origin. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 5. Vectors that have the same or opposite direction but not necessarily the same magnitude are known as 8. 9. . if its initial point 10. Define each term in your own words. 11. true bearing 12. resultant Chapter 8 36 Glencoe Precalculus NAME DATE 8 PERIOD Chapter 8 Test, Form 1 SCORE Write the letter for the correct answer in the blank at the right of each question. 1. Find the vertical component of v with a magnitude of 5 inches and a direction angle of 32°. A 2.65 in. B 2.79 in. C 4.24 in. D 31.88 in. 1. F 〈- −15 , −15 〉 G 〈8, -6〉 H 〈- −35 , −45 〉 J 〈−35 , - −45 〉 2. 3. Find the resultant of the pair of vectors using either the triangle method or the parallelogram method. State the magnitude of the resultant in centimeters. A 2 cm C 4.95 cm B 3.5 cm D 5.25 cm a 3. b 4. Find the measure of the angle θ between vectors a = 〈4, 6〉 and b = 〈2, 8〉 to the nearest tenth of a degree. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. F 19.7° G 43.3° H 70.4° J 102.3° 4. ⎯⎯⎯⎯ with initial point A(1, 2) 5. Find the component form and magnitude of AB and terminal point B(0, 3). A 〈-1, 1〉; 1.41 B 〈1, -1〉; 2 C 〈-1, -1〉; 1.41 D 〈1,1〉; 2 5. 6. A force F1 of 9 newtons pulls due north. A force F2 of 12 newtons pulls due east. Find the magnitude and direction of the resultant force. F 15 N; 36.9° G 15 N; 53.1° H 21 N; 36.9° J 21 N; 53.1° 6. For Questions 7 and 8, find each of the following for v = 〈3, −4〉, w = 〈3, −1〉, r = 〈2, 7, −2〉, and s = 〈-3, 4, 9〉. 7. 2v + w A 〈6, −5〉 B 〈6, −6〉 C 〈9, −9〉 D 〈9, -10〉 7. G 〈1, −13, −7〉 H 〈−5, −3, 11〉 J 〈5, 3, −11〉 8. 8. r - s F 〈−1, 13, 7〉 9. Erin pushes a box up a ramp with a constant force of 60 newtons at a constant angle of 25°. Find the work done in joules to move the box 5 meters. A 126.7 J B 139.9 J C 225.8 J D 271.9 J 9. 10. Find the cross product of v = 〈-1, 2, 4〉 and w = 〈-3, -1, 5〉. F 〈14, -7, -5〉 Chapter 8 G 〈14, 7, 7〉 H 〈14, -7, 7〉 37 J 〈6, -7, 7〉 10. Glencoe Precalculus Assessment 2. Find a unit vector u with the same direction as v = 〈−3, 4〉. NAME DATE 8 Chapter 8 Test, Form 1 PERIOD (continued) 11. Find the measure of the angle θ between u = 〈2, 1, 3〉 and v = 〈−4, 3, 0〉 to the nearest tenth of a degree. A -15.5° B 36.1° C 54.0° D 105.5° 11. For Questions 12 and 13, find each dot product. Then determine if the vectors are orthogonal. 12. 〈2, 3〉·〈4, 5〉 F 22, orthogonal G 22, not orthogonal H 23, orthogonal J 23, not orthogonal 12. 13. 〈3, 0, −2〉 · 〈4, −2, 6〉 A 0, orthogonal B 0, not orthogonal C 9, orthogonal D 9, not orthogonal 13. 14. A constant force of 42 newtons is being applied on an object in the direction of due east at the same time that a constant force of 35 newtons is being applied on the object in the direction of due north. What is the magnitude and direction of the force? F 38.5 N, 39.8° G 38.5 N, 50.2° H 54.7 N, 39.8° J 54.7 N, 50.2° 14. 15. 16. A cruise ship’s path is represented by the vector 〈9, 17〉. It then follows a new path represented by the vector 〈12, 8〉. What is the resultant path? F 〈3, 9〉 G 〈21, 25〉 H 〈−3, 9〉 J 〈−21, 25〉 16. 16 24 , −− 〈− 13 〉 13 17. 17. Find the projection of u = 〈4, 2〉 onto v = 〈−3, 2〉. A 3 2 ,− 〈− − 13 13 〉 B 4 2 ,− 〈− 13 13 〉 C 32 16 , −− 〈− − 13 13 〉 18. Find the area of the parallelogram with adjacent sides u = 〈-3, 4, 8〉 and v = 〈9, -1, 6〉. F 32 units2 G 76 units2 H 82.7 units2 D J 101.1 units2 18. 19. The position of one airplane is represented by 〈9, 5, 3〉 and a second airplane is represented by 〈−7, 7, 4〉. Determine the distance between the planes if one unit represents one mile. A 9.5 mi B 14.0 mi C 15.8 mi D 16.2 mi 19. 20. Find the volume of the parallelepiped with adjacent edges u = 〈2, 3, 0〉, v = 〈−4, 5, 1〉, and w = 〈−2, 3, 4〉. F 8 units3 G 20 units3 H 76 units3 20. Bonus Find the cross product of v and -2w if v = 〈2, 4, −1〉 and w = 〈−1, 2, -5〉. Chapter 8 38 J 88 units3 B: Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 15. An airplane takes off in the direction of the vector 〈9, 5〉. What is the measure of the angle the plane makes with the horizontal? A 29.1° B 33.7° C 56.3° D 60.9° NAME DATE 8 PERIOD Chapter 8 Test, Form 2A SCORE Write the letter for the correct answer in the blank at the right of each question. 1. Find the vertical component of v with a magnitude of 89.7 feet and a direction angle of 12.8°. A 19.38 ft B 19.87 ft C 87.58 ft D 887.47 ft 1. 2. Find a unit vector u with the same direction as v = 〈−2, 4〉. 〈- −25 , −25 〉 √ √ G 〈4, −2〉 H 2 5 〈- −55 , − 5 〉 √ √ J 2 5 〈−55 , - − 5 〉 √ √ 2. 3. Find the resultant of the sum of the pair of vectors using either the triangle method or the parallelogram method. State the magnitude in centimeters. A 3.73 cm; 55.4° C 5.0 cm; 55.4 ° B 3.73 cm; 90° D 5.0 cm; 90° 3. a b 4. Find the measure of the angle θ between vectors a = 〈5, 6〉 and b = 〈−2, 8〉 to the nearest tenth of a degree. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. F 53.8° G 36.2° H 30.5° J 28.5° 4. ⎯⎯⎯⎯ with initial point 5. Find the component form and magnitude of AB A(9, 2) and terminal point B(−6, 3). A 〈-15, 1〉; 15.03 B 〈3, 5〉; 5.83 C 〈15, -1〉; 3.74 D 〈3, 1〉; 3.16 5. 6. A force F1 of 12 newtons pulls due north. A force F2 of 5 newtons pulls due east. Find the magnitude and direction of the resultant force. F 13 N; 22.6° G 17 N; 22.6° H 13 N; 67.4° J 17 N; 67.4° 6. For Questions 7 and 8, find each of the following for v = 〈−4, 0〉, w = 〈−3, 4〉, r = 〈−3, 7, 2〉, and s = 〈6, −3, 5〉. 7. 4w − 2v A 〈−20, 16〉 B 〈−4, 16〉 C 〈−10, −8 〉 D 〈−22, 8〉 7. G 〈15, 13, 12〉 H 〈−15, 13, −8〉 J 〈−9, 10, −3〉 8. 8. r – 2s F 〈9, 1, −8〉 9. Arjon pushes a box up a ramp with a constant force of 45.8 newtons at a constant angle of 55°. Find the work done in joules to move the box 8 meters. A 183.8 J B 210.2 J C 300.1 J D 523.3 J 9. 10. Find the cross product of v = 〈-9, 4, -8〉 and w = 〈6, −2, 4〉. F 〈−54, −8, −32〉 Chapter 8 G 〈0, −12, −6〉 H 〈32, 84, 42〉 39 J 〈−6, −12, 0〉 10. Glencoe Precalculus Assessment F NAME DATE 8 Chapter 8 Test, Form 2A PERIOD (continued) 11. Find the measure of the angle θ between u = 〈3, −2, 0〉 and v = 〈−4, 3, 1〉 to the nearest tenth of a degree. A 11.7° B 109.0° C 168.3° 11. D 176.8° For Questions 12 and 13, find each dot product. Then determine if the vectors are orthogonal. 12. a · b for a = −8i + 3j and b = 4i + 6j F −50, not orthogonal G 0, orthogonal 〈 〉 〈2 H −14, not orthogonal J 21, not orthogonal 12. C 5, orthogonal D 0, not orthogonal 13. 〉 5 3 1 1 , −− · − , −2, − − 13. 4, − 4 3 2 A 5, not orthogonal B 0, orthogonal 14. A constant force of 18 newtons is being applied at a constant angle of 56° on an object at the same time that a constant force of 32 newtons at a constant angle of 124° is acting on the object. What is the magnitude and direction of the resultant force? F 42.2 N; 100.7° G 42.2 N; 280.7° H 44.6 N; 36.5° J 44.6 N; 216.5° 14. 15. An airplane is traveling due east with a velocity of 550 miles per hour. The wind blows at 80 miles per hour at an angle of 40° North of East. Determine the velocity of the airplane’s flight. B 611.3 mph C 613.4 mph D 630 mph 15. 16. A cruise ship’s path is represented by the vector 〈−2, 12〉. It then follows a new path represented by the vector 〈7, 6〉. What is the resultant path? F 〈9, 6〉 G 〈9, 18〉 H 〈5, 6〉 J 〈5, 18〉 16. 17. Find the projection of u = 〈−4, 8〉 onto v = 〈3, 12〉. A 28 112 ,− 〈− 17 17 〉 B 17 17 ,− 〈− 28 112 〉 C 112 224 ,− 〈- − 51 51 〉 D 51 51 ,− 〈- − 112 224 〉 17. 18. Find the area of the parallelogram with adjacent sides u = 〈23, 14, −28〉 and v = 〈12, 16, 13〉. F 200 units2 G 630 units2 H 635 units2 J 916.6 units2 18. 19. The position of one airplane is represented by 〈−9, 8, 2.5) and a second airplane is represented by 〈12, 2, 5). Determine the distance between the planes if one unit represents one mile. A 22.0 mi B 38.5 mi C 45.8 mi D 56.7 mi 19. J 230 units3 20. 20. Find the volume of the parallelepiped with adjacent edges u = 〈1, −4, 2〉, v = 〈6, −5, 1〉, and w = 〈3, −4, −8〉. F 90 units3 G 126 units3 H 178 units3 3 1 Bonus Find the cross product of - − v and − w if 2 4 v = 〈−2, 12, −3〉 and w = 〈−7, 4, -6〉. Chapter 8 40 B: Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. A 601.4 mph NAME DATE 8 PERIOD Chapter 8 Test, Form 2B SCORE Write the letter for the correct answer in the blank at the right of each question. 1. Find the vertical component of v with a magnitude of 6.1 inches and a direction angle of 55°. A 3.50 in. B 5.00 in. C 7.45 in. D 10.64 in. 1. F 〈- −25 , −25 〉 √ √ G 〈−6, −3〉 H 〈- −, −〉 √5 2 √5 5 5 J 2 5 〈- −55 , - − 5 〉 √ √ 2. 3. Find the resultant of the pair of vectors using either the triangle method or the parallelogram method. State the magnitude of the resultant in centimeters. A 2.5 cm; 50.8° C 2.8 cm; 50.8° B 2.5 cm; 39.2° D 2.8 cm; 39.2° a 3. b 4. Find the measure of the angle θ between the vectors a = 〈−15, 4〉 and b = 〈3, 10〉 to the nearest tenth of a degree. F 62.4° G 71.6° H 87.1° J 91.8° 4. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. ⎯⎯⎯⎯ with initial point A(−4.3, −0.9) 5. Find the component form and magnitude of AB ⎯⎯⎯⎯. and terminal point B(−2.8, 0.2). Then find the magnitude of AB A 〈1.5, 1.1〉; 3.46 C 〈1.5, 1.1〉; 1.86 B 〈−7.1, −0.7〉; 7.13 D 〈−7.1, −1.1〉; 7.18 5. 6. A force F1 of 6 newtons pulls due north. A force F2 of 8 newtons pulls due east. Find the magnitude and direction of the resultant force. F 10 N; 53.1° G 14 N; 53.1° H 10 N; 36.9° J 14 N; 36.9° 6. For Questions 7 and 8, find each of the following for v = 〈−4, 0〉, w = 〈−2, 4〉, r = 〈−3, 7, 2〉, and s = 〈6, −3, 5〉. 7. 3w − 4v A 〈−22, 12〉 B 〈−6, 0〉 C 〈−10, −12 〉 D 〈10, 12〉 7. G 〈−12, 17, −1〉 H 〈−15, 1, −8〉 J 〈0, 11, 9〉 8. 8. 2r – s F 〈9, 1, −8〉 9. Jerard pushes a box up a ramp with a constant force of 55.2 newtons at a constant angle of 22°. Find the work done in joules to move the box 4 meters. A 82.7 J B 89.2 J C 157.3 J D 204.7 J 9. 10. Find the cross product of v = 〈-5, 4, -8〉 and w = 〈6, -2, 6〉. F 〈34, -78, 34〉 Chapter 8 G 〈-8, 16, 14〉 H 〈8, -16, -14〉 41 J 〈-34, 78, -34〉 10. Glencoe Precalculus Assessment 2. Find a unit vector u with the same direction as v = 〈−3, −6〉. NAME DATE 8 Chapter 8 Test, Form 2B PERIOD (continued) 11. Find the measure of the angle θ between u = 〈−3, −2, 1〉 and v = 〈−4, 3, 0〉 to the nearest tenth of a degree. A 15.8° B 71.3° C 108.7° D 164.2° 11. For Questions 12 and 13, find each dot product. Then determine if the vectors are orthogonal. 12. a · b for a = 8i + 3j and b = −4i − 6j F −50, not orthogonal G 1, orthogonal H −14, orthogonal J 13, orthogonal 12. C −32, orthogonal D −32, not orthogonal 13. 13. 〈4, −2, −2〉 · 〈-7, −2, 4〉 A 0, orthogonal B −40, not orthogonal 14. A constant force of 22 newtons is being applied at a constant angle of 48° on an object at the same time that a constant force of 54 newtons is being applied at a constant angle of 135°. What is the magnitude and direction of the resultant force? F 56.5 N, 66.7° G 59.3 N, 113.3° H 56.5 N, 113.3° J 59.4 N, 66.7° 14. 15. An airplane is traveling due east with a velocity of 620 miles per hour. The wind blows at 45 miles per hour at an angle of 30° North of East. Determine the velocity of the airplane’s flight. B 636.6 mph C 659.4 mph D 665 mph 15. 16. A cruise ship’s path is represented by the vector 〈8, −2〉. It then follows a new path represented by the vector 〈−2, −8〉. What is the resultant path? F 〈10, −12〉 G 〈10, −4〉 H 〈6, −10〉 J 〈6, −4〉 16. 17. Find the projection of u = 〈3, −12〉 onto v = 〈9, 2〉. A 27 6 ,− 〈− 85 85 〉 B 85 85 ,− 〈− 27 6 〉 C 9 36 , -− 〈− 85 85 〉 D 85 85 , -− 〈− 9 36 〉 17. 18. Find the area of the parallelogram with adjacent sides u = 〈6, −8, −31〉 and v = 〈53, 7, 21〉. F 1727.0 units2 G 1785.8 units2 H 1830.0 units2 J 2132.4 units2 18. 19. The position of one airplane is represented by 〈12, 2, 3.7〉 and a second airplane is represented by 〈−1, 7, 5.2〉. Determine the distance between the planes if one unit represents one mile. A 14.0 mi B 16.8 mi C 26.6 mi D 48.9 mi 19. J 236 units3 20. 20. Find the volume of the parallelepiped with adjacent edges u = 〈1, 2, 2〉, v = 〈6, −5, 1〉, and w = 〈6, −4, −8〉. F 68 units3 G 132 units3 H 164 units3 Bonus Find the cross product of 3v and -2w if v = 〈−1, 5, 3〉 and w = 〈−7, 5, -6〉. Chapter 8 42 B: Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. A 536.9 mph NAME DATE 8 Chapter 8 Test, Form 2C PERIOD SCORE 1. The vector v has a magnitude of 10 meters and a direction of 92°. Find the magnitude of its vertical and horizontal components. 1. 2. Find a unit vector u with the same direction as v = 〈-3, 5〉. 2. B Assessment 3. Find a - 3b for the pair of vectors below using either the triangle method or the parallelogram method. State the magnitude of the resultant in centimeters and its direction relative to the horizontal. C 3. 4. Find the measure of the angle θ between u = 3i - 4 j and v = i + 2 j. 4. ⎯⎯⎯⎯ with initial 5. Find the component form and magnitude of AB point A(0, -8) and terminal point B(−1, 7). 5. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 6. A force F1 of 27 newtons pulls at an angle of 23° above due east. A force F2 of 33 newtons pulls at an angle of 55° below due west. Find the magnitude and direction of the resultant force. 6. For Questions 7 and 8, find each of the following for v = 〈1, −6〉, w = 〈2, −5〉, r = 〈1, −1, 0〉, and s = 〈10, −6, 5〉. 7. v + 3w 7. 8. 3s - 2r 8. 9. Jerard pushes a box up a ramp with a constant force of 41.5 newtons at a constant angle of 28°. Find the work done in joules to move the box 5 meters. 9. 10. Find the cross product of v = 〈6, −4, 3〉 and w = 〈4, 2, -6〉. 10. 11. Find the measure of the angle θ between u = 〈4, −2, 1〉 and v = 〈−3, 5, 0〉 to the nearest tenth of a degree. 11. For Questions 12 and 13, find each dot product. Then determine if the vectors are orthogonal. 12. 〈8, 2〉 · 〈0, −6〉 12. 13. 〈3, −7, 4〉 · 〈−4, −2, 1〉 13. Chapter 8 43 Glencoe Precalculus NAME 8 DATE Chapter 8 Test, Form 2C PERIOD (continued) 14. A constant force of 15 newtons is being applied at a constant angle of 30° on an object at the same time that a constant force of 25 newtons at a constant angle of 60° is acting on the object. What is the magnitude and direction of the resultant force? 14. 15. An airplane is traveling due east with a velocity of 620 miles per hour. The wind blows at 60 miles per hour at an angle of 50° with the horizontal. Determine the velocity of the airplane’s flight. 15. 16. 17. Find the projection of u = 〈7, -2〉 onto v = 〈−1, 5〉. 17. 18. Find the surface area of the parallelepiped with adjacent edges u = 〈8, 3, −3〉 and v = 〈−8, 9, 13〉, and w = 〈7, −2, −7〉. 18. 19. The position of one airplane is represented by 〈9, 13, 4〉 and a second airplane is represented by 〈−7, 12, 3〉. Determine the distance between the planes if one unit represents one mile. 19. 20. Find the volume of the parallelepiped with adjacent edges u = 〈0.5, −3, 2〉, v = 〈−7, −0.5, 1〉, and w = 〈−4, 7, −8〉. 20. Bonus If v = 〈v1, v2〉, where v1 and v2 are not both 0 and u = −3v, find the measure of the angle between u and v. Chapter 8 44 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 16. A cruise ship’s path travels for 24.7 miles at an angle of 58.2°. It then follows a path can be represented by the vector 〈22, 31〉. What is the resultant path? B: Glencoe Precalculus NAME DATE 8 Chapter 8 Test, Form 2D PERIOD SCORE 1. The vector v has a magnitude of 5 meters and a direction of 60°. Find the magnitude of its vertical and horizontal components. 1. 2. Find a unit vector u with the same direction as v = 〈−3, 8〉. 2. B Assessment 1 3. Find −− a + b for the pair of vectors below using either the 2 triangle method or the parallelogram method. State the magnitude of the resultant in centimeters and its direction relative to the horizontal. C 3. 4. Find the measure of the angle θ between u = 6i - 3 j and v = 2i + j to the nearest tenth of a degree. 4. ⎯⎯⎯⎯ with initial 5. Find the component form and magnitude of AB point A(3, −1) and terminal point B(−1, −2). 5. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 6. A force F1 of 25 newtons pulls at an angle of 20° above due east. A force F2 of 35 newtons pulls at an angle of 55° below due west. 6. Find the magnitude and direction of the resultant force. For Questions 7 and 8, find each of the following for v = 〈2, −3〉, w = 〈1, 5〉, r = 〈1, −1, 1〉, and s = 〈0, −3, 2〉. 7. −2v + w 7. 8. 3s + r 8. 9. Harold pushes a box up a ramp with a constant force of 31.5 newtons at a constant angle of 32°. Find the work done in joules to move the box 8 meters. 9. 10. Find the cross product of v = 〈2, −1, 3〉 and w = 〈1, 0, −5〉. 10. 11. Find the measure of the angle θ between u = 〈−2, −2, 1〉 and v = 〈−3, 4, 0〉 to the nearest tenth of a degree. 11. For Questions 12 and 13, find each dot product. Then determine if the vectors are orthogonal. 12. 〈2, 0〉 · 〈0, −5〉 12. 13. 〈3, −4, −2〉 · 〈−2, −2, 3〉 13. Chapter 8 45 Glencoe Precalculus NAME 8 DATE Chapter 8 Test, Form 2D PERIOD (continued) 14. 15. An airplane is traveling due east with a velocity of 580 miles per hour. The wind blows at 50 miles per hour at an angle of 45° to the horizontal. Determine the velocity of the airplane’s flight. 15. 16. A cruise ship’s path travels for 16.1 miles at an angle of 60.3°. It then follows a path that can be represented by the vector 〈22, 7〉. What is the resultant path? 16. 17. Find the projection of u = 〈9, −5〉 onto v = 〈3,−2〉. 17. 18. Find the surface area of the parallelepiped with adjacent edges u = 〈4, 7, −8〉, v = 〈−2, 5, 11〉, and w = 〈9, −2, −8〉. 18. 19. The position of one airplane is represented by 〈11, 10, 3〉 and a second airplane is represented by 〈−9, 14, 3〉. Determine the distance between the planes if one unit represents one mile. 19. 20. Find the volume of the parallelepiped with adjacent edges u = 〈-2, 0.75, 4〉, v = 〈6, −0.3, 8〉, and w = 〈3, −2.5, 9〉. 20. Bonus If v = 〈v1, v2〉 where v1 and v2 are not both 0 and u = 2v, find the measure of the angle between u and v. B: Chapter 8 46 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 14. A constant force of 10 newtons is being applied at a constant angle of 45° on an object at the same time that a constant force of 20 newtons at a constant angle of 65° is acting on the object. What is the magnitude and direction of the resultant force? Glencoe Precalculus NAME DATE 8 PERIOD Chapter 8 Test, Form 3 SCORE 1. The vector v has a magnitude of 11.4 meters and a direction of 248°. Find the magnitude of its vertical and horizontal components. 1. 2. Find a unit vector u with the same direction as v = 〈−6, −2〉. 2. B Assessment 1 2 3. Find −3a + − b+− a for the pair of vectors below using 2 3 either the triangle method or the parallelogram method. State the magnitude of the resultant in centimeters and its direction relative to the horizontal. C Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 3. 4. Find the measure of the angle θ between u = 4i - 8j and v = 2i - 5j. 4. ⎯⎯⎯⎯ with initial 5. Find the component form and magnitude of AB point A(1.8, −3.8) and terminal point B(−0.1, −3.8). 5. 6. A force F1 of 18.8 newtons pulls at an angle of 12° north of east. A force F2 of 3.2 newtons pulls at an angle of 55° south of east. Find the magnitude and direction of the resultant force. 6. For Questions 7 and 8, find each of the following for 〈 〈 2〉 〉 〈 〈 〉 〉 3 3 1 1 , w = 2, - − , r = 1, − − , 2 , and s = 10, −6, − . v = 0, − 4 4 4 1 7. −v + − w 7. 1 8. − r + 4s 8. 9. Kyle is pulling a box east with a force of 300 newtons at a constant angle of 42° to the horizontal. Jerome is pushing the box from behind with a force of 350 newtons due east. Determine the magnitude and direction of the resultant force on the box. 9. 3 2 〈 〉 〈 〉 1 1 10. Find the cross product of v = 6, − − , 3 and w = 4, 2, − − . 2 〈 3 1 ,4 11. Find the measure of the angle θ between u = −4, − − 〈 〉 1 . and v = −3, −4, − Chapter 8 3 47 2 〉 10. 11. Glencoe Precalculus NAME 8 DATE Chapter 8 Test, Form 3 PERIOD (continued) For Questions 12 and 13, find each dot product. Then determine if the vectors are orthogonal. 〈 3〉 〈2 2 1 12. 8, − · − , −6 〉 12. 〈 〉 1 13. 〈−2, 6, 8〉 · −4, −2, − − 2 13. 14. A constant force of 12.2 newtons is being applied at a constant angle of 12° on an object at the same time that a constant force of 18.9 newtons at a constant angle of 75.8° is acting on the object. What is the magnitude and direction of the resultant force? 14. 15. An airplane is traveling with a velocity of 300 miles per hour at an angle 45° to the north of east. If a 40-mile per hour wind is blowing from a bearing of 130°, determine the velocity and direction of the airplane relative to the ground. 15. 〈 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 16. A cruise ship starts on a path represented by the vector 〈9, -10〉. It then changes direction and the path can be represented by the vector 〈3, -13〉. Another ship’s path is represented by the path 〈14, -4〉. If the second ship changes direction, what vector represents the path the second ship would need to take to end up at the same place as the first ship? 16. 〉 3 17. Find the projection of u = − , −4 onto a vector v with a length 2 17. of 2.8 units and a direction angle of 35°. 18. Find the surface area of the parallelepiped with adjacent edges 1 1 u = 〈3, 5, 9〉 and v = 3, − , 8 and w = 2, −4, − . 18. 19. Two airplanes are flying to the same airport. The position of the first airplane is (5, -9, 2.5) and the position of the second airplane is (-8, 7, 2). The airport is at (3, 3, 0.5). Which airplane is closer to the airport if the positions are given in miles? How much closer? 19. 20. Find the volume of the parallelepiped with adjacent edges u = −3i + 2.75j + k, v = 4i −1.3j + 8k, and w = −3i − 0.5j + 2k. 20. Bonus If v = 〈v1, v2〉 where v1 and v2 are not both 0 and u = -2v and w = 5v, find the measure of the angle between u and w. B: 〈 Chapter 8 4 〉 〈 2 48 〉 Glencoe Precalculus NAME DATE 8 Extended-Response Test PERIOD SCORE Demonstrate your knowledge by giving a clear, concise solution to each problem. Be sure to include all relevant drawings and justify your answers. You may show your solution in more than one way or investigate beyond the requirements of the problem. 1. Given the vectors below, complete the questions that follow. 30° C 30° c = 〈-3, 1〉 and d = 〈-8, -11〉 Assessment B a. Show two ways to find a + b. b. Find a - b. Explain each step. c. Does a + b = b + a? Why or why not? d. Does a - b = b - a? Defend your answer. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. e. Tell how to find the sum c + d. Find the sum and its magnitude. f. Find two vectors whose difference is 〈4, -1, 3〉. Write the difference as a linear combination. g. Find a vector perpendicular to 〈7, -3〉. Explain how you know that the two vectors are perpendicular. h. Find a × b if a = 〈2, 1, 0〉 and b = 〈1, 3, 0〉. Graph the vectors and the cross product c in three dimensions. 2. An airplane can be represented by the point (9, 8, 5). The airport can be represented by the point (8, -3, 0). a. How far away from the airport is the plane? b. A second plane can be represented by the point (10, -6, 4). How far away from the airport is the second plane? c. If the first plane is moving at 200 miles per hour and the second plane is moving at 150 miles per hour, which plane will be at the airport first? 3. Find two pairs of perpendicular vectors. Then verify that they are perpendicular by calculating their dot products. Chapter 8 49 Glencoe Precalculus NAME DATE PERIOD 8 Standardized Test Practice SCORE (Chapters 1–8) Part 1: Multiple Choice Instructions: Fill in the appropriate circle for the best answer. 1. Find the period and phase shift of the graph of f (x) = -4 cos (2x + π). A 2, 4 right B 2π, π left π left C π, − D 2, π right H 1 J − 2 1. A B C D √3 2 2. F G H J D 17 3. A B C D 1 J f-1(x) = - − 4. F G H J 3π 2. Find the value of sin − . 2 √3 2 G −1 F -− 3. Find the cross product of u = 〈8, -3, 9〉 and v = 〈−2, 3, 2〉. B 〈-33, -34, 18〉 C −7 A 〈-33, 34, 18〉 4. Find f -1(x) if f (x) = −8x - 3. x+3 8 F f-1(x) = − x+3 8 1 G f-1(x) = - − H f-1(x) = − 8x + 3 8x + 3 5. The graph of g(x) = (x + 3)3 + 4 can be obtained from the graph of f (x) = x3 by performing which transformation? C move right 3 and down 4 B move left 3 and up 4 D move left 3 and down 4 5. A B C D H 10 J 64 6. F G H J D 〈-11, 12〉 7. A B C D 8. F G H J 9. A B C D 10. F G H J 4 -2 1 6. Find the value of 0 8 -4 . 2 2 -1 F -16 G 0 7. Let u = 〈5, 3〉 and v = 〈-7, 2〉. Find 2u + 3v. A 〈10, 6〉 B 〈−21, 6〉 C 〈−11, 6〉 8. If f(x) = -3x + 7 and g(x) = 2x - 4, find f (g(x)). F f (g(x)) = -6x + 12 H f (g(x)) =−6x + 10 G f (g(x)) = −6x + 19 J f (g(x)) = −6x + 14 ⎡ 9 -2⎤ ⎡ 3 1 ⎤ 9. Find the element in row 1, column 2 of the product ⎢ . ⎢ ⎣-1 5⎦ ⎣ 2 -4 ⎦ A −2 B -1 C 7 D 17 G 6 H 8 J 4096 10. Find log2 64. F 2 Chapter 8 50 Glencoe Precalculus Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. A move right 3 and up 4 NAME DATE 8 Standardized Test Practice PERIOD (continued) (Chapters 1–8) 11. Solve log3 x = 5. A 3 B 8 C 15 D 243 11. A B C D 12. F G H J D the line y = x 13. A B C D 14. F G H J 15. A B C D 16. F G H J A relative maximum of −7 at x = 1 C relative maximum of 0 at x = -6 B relative minimum of −7 at x = 1 D relative minimum of 0 at x = −6 17. A B C D 18. F G H J 19. A B C D F G H J F 8 G 32 H 22 J 40 13. The graph of f (x) = 2x3 + 17x is symmetric with respect to which of the following? A the x-axis B the y-axis C the origin 14. Given that f (x) = 4x2 - 3x + 2, what is the value of f (−3)? F −25 G 12 H 29 J 47 15. What are the zeros of f (x) = 2x2 + 3x - 5? A -1, 5 B −5, 1 5 C -− ,1 2 5 D −1, − 2 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 16. Choose the statement that is true for the graph of f (x) = −2(x - 3)4. F f (x) increases for x > -3. H f (x) increases for x > 3. G f (x) decreases for x < -3. J f (x) decreases for x > 3. 17. Which is true for the graph of f (x) = 2x3 - 3x2 - 6? ⎧ 3x - 9 if x < -3 18. Evaluate g(3) for g(x)= 2x2 - 15 if 0 < x < 2. ⎩ −x + 12 if x > 2 ⎨ F 0 G 3 H 9 J 15 19. The height of a softball thrown straight up into the air can be modeled by the function h(t) = −4.9t2 + 4t + 2, where t is the time in seconds after the ball is released and h(t) is the height of the ball in meters. What is the highest point the ball reaches? A 2.0 m B 2.8 m C 3.1 m D 4.5 m 20. Marina deposited $8000 in an account paying 4.5% interest compounded continuously. How long would it take for the balance in the account to double? F 9.0 yr Chapter 8 G 15.4 yr H 20.0 yr 51 J 27.6 yr 20. Glencoe Precalculus Assessment 12. What is the remainder of f (x) = 3x3 + 4x2 - 8 divided by x - 2? NAME DATE 8 Standardized Test Practice PERIOD (continued) (Chapters 1–8) Part 2: Short Response Instructions: Write your answers in the space provided. π ,a 21. Write an equation of the sine curve that has a period of − 3 vertical shift of 9, and an amplitude of 3. 21. 22. Find the equations of the vertical asymptote(s) of the 3x2 + 5x - 6 x-5 22. function f(x) = − . 23. An athlete is running at 4.6 meters per second and throws a javelin at 8 meters per second at an angle of 50°. What is the 23. resulting speed and direction of the javelin? ⎡6 8 x⎤ ⎡-1 4⎤ ⎡ 18 70⎤ 24. 24. Find the value of x and y. 1 -2 1 3 y = -7 -9 ⎣0 3 6⎦ ⎣ 0 -3⎦ ⎣ 9 -3⎦ ⎢ ⎢ ⎢ 25. A horse is pulling a wagon with a constant force of 1500 N. The harness makes an angle of 28° with the wagon. Find the work done in joules to pull the wagon 50 meters. 25. 26. What is the angle between the vectors u = 〈2, −3, 4〉 and v = 〈9, 0, -1〉? 26. " $ # Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 27. If AB = 22.5 and AC = 13.8, find CB and the measure of each angle. 27. 28. Mary is in a canoe crossing a river that has a current flowing at 3.2 meters per second due east. Mary begins paddling across the river at 3.4 meters per second at an angle of 70° with the bank. Find the magnitude and direction of the canoe’s path. 28. 29. Write an equation for a circle that has its center at (9, −2) and a radius of 5 units. 29. 30. Two airplanes are flying to an airport that can be represented by the point (30, 22, 1). The first airplane’s position can be represented by the point (-15, 4, 2.5) and the second plane’s position can be represented by the point (43, -6, 3). Each unit represents 1 mile. a. What vector represents the direct path from the first plane to the airport? 30a. b. What vector represents the direct path from the second plane to the airport? 30b. c. Which plane is closer to the airport, the first plane or the second plane? How much closer? 30c. Chapter 8 52 Glencoe Precalculus Chapter 8 A1 Glencoe Precalculus Before you begin Chapter 8 Vectors Anticipation Guide DATE PERIOD After you complete Chapter 8 12. The area of a parallelogram can be found using dot products. 10. Vectors can be used to represent forces in three-dimensional space. 11. When finding torque, the dot product is used. 6. Any vector can be broken down into horizontal and vertical components. 7. To add two vectors algebraically, add all of the numbers in the first vector together. Then add all of the numbers in the second vector together. 8. Trigonometric ratios sometimes need to be used when working with vectors. 9. The dot product of two vectors is a scalar. 5. When vectors are combined the result is a scalar. 3. The initial point of a vector is the point where the vector starts. 4. Vectors can be used to represent forces applied at an angle. 2. Vectors can be represented by directed line segments. 1. Scalars have both magnitude and direction. Statement 3 10/23/09 11:05:00 AM Glencoe Precalculus PERIOD 0 Y 125° 8 0 4 X & 1 cm: 20 mi/h 45° / Using a scale of 1 cm.: 20 mi/h, draw and label a 55 ÷ 20 or 2.75-centimeter arrow 45° east of south. b. w = 55 miles per hour at a bearing of S45°E 45° 0 1 cm: 50 yd 40° U 005_032_PCCRMC08_893809.indd 5 Answers Chapter 8 3. 2.2 cm, 140° C B S 5 4. F G F Lesson 8-1 10/23/09 11:17:57 AM Glencoe Precalculus 3.5 cm, -12° S G 2. t = 150 yards at 40° to the horizontal Find the resultant of each pair of vectors using either the triangle or parallelogram method. State the magnitude of the resultant in centimeters and its direction relative to the horizontal. 8 1 cm: 10 m S / 1. r = 30 meters at a bearing of N45°W Use a ruler and a protractor to draw an arrow diagram for each quantity described. Include a scale on each diagram. Exercises 1 cm: 20 lb W Z Using a scale of 1 cm: 20 lb, draw and label a 60 ÷ 20 or 3-centimeter arrow in standard position at a 125° angle to the x-axis. a. v = 60 pounds of force at 125° to the horizontal Example Use a ruler and a protractor to draw an arrow diagram for each quantity described. Include a scale on each diagram. A vector is a quantity that has both magnitude and direction. The magnitude of a vector is the length of a directed line segment, and the direction of a vector is the directed angle between the positive x-axis and the vector. When adding or subtracting vectors, you can use the parallelogram or triangle method to find the resultant. Introduction to Vectors C Chapter 8 DATE Study Guide and Intervention Geometric Vectors 8-1 NAME • For those statements that you mark with a D, use a piece of paper to write an example of why you disagree. Chapter Resources B D D A A A D A A D A D A STEP 2 A or D Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. • Did any of your opinions about the statements change from the first column? • Reread each statement and complete the last column by entering an A or a D. Step 2 STEP 1 A, D, or NS • Write A or D in the first column OR if you are not sure whether you agree or disagree, write NS (Not Sure). • Decide whether you Agree (A) or Disagree (D) with the statement. • Read each statement. Step 1 8 NAME 0ii_004_PCCRMC08_893809.indd Sec1:3 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Answers (Anticipation Guide and Lesson 8-1) (continued) PERIOD 60° x 50 N y A2 Use a calculator. ⎪x⎥ = 25 ⎪y ⎥ ⎪y⎥ ≈ 43.3 ⎪y⎥ = 50 sin 60° 50 sin 60° = − 120° 8 50° 2.5 cm 4 / & 2. 2.5 centimeters per hour at a bearing of N50°W -1.9, 1.6 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 6 Chapter 8 6 Glencoe Precalculus 4. TRANSPORTATION A helicopter is moving 15° north of east with a velocity of 52 km/h. If a 30-kilometer per hour wind is blowing from a bearing of 250°, find the helicopter’s resulting velocity and direction. 81.93 km/h; 16.8° north of east 3. YARDWORK Nadia is pulling a tarp along level ground with a force of 25 pounds directed along the tarp. If the tarp makes an angle of 50° with the ground, find the horizontal and vertical components of the force. What is the magnitude and direction of the resultant? 16.07 lb; 19.15 lb; 25 lb; 50° 7 in. 1. 7 inches at a bearing of 120° from the horizontal -3.5, 6.1 Draw a diagram that shows the resolution of each vector into its rectangular components. Then find the magnitudes of the vector’s horizontal and vertical components. Exercises The magnitude of the horizontal component is about 25 Newtons, and the magnitude of the vertical component is about 43 Newtons. Solve for x and y. Right triangle definitions of cosine and sine ⎪x⎥ = 50 cos 60° 50 cos 60° = − ⎪ x⎥ The horizontal and vertical components of the force form a right triangle. Use the sine or cosine ratios to find the magnitude of each force. b. Find the magnitudes of the horizontal and vertical components of the force. Jamal’s pull can be resolved into a horizontal pull x forward and a vertical pull y upward as shown. a. Draw a diagram that shows the resolution of the force Jamal exerts into its rectangular components. Example Suppose Jamal pulls on the ends of a rope tied to a dinghy with a force of 50 Newtons at an angle of 60° with the horizontal. Vectors can be resolved into horizontal and vertical components. Introduction to Vectors Study Guide and Intervention DATE 10/23/09 11:25:56 AM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 Vector Applications 8-1 NAME Introduction to Vectors Practice DATE PERIOD 4 45° 1 cm: 20 m S & Z U 1 cm: 25 lb 60° Y 2. t = 100 pounds of force at 60° to the horizontal 8 1000 45° 4 / & Y Z Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 7 Chapter 8 bearing of 354.3° 7 Lesson 8-1 10/23/09 11:09:29 AM Glencoe Precalculus 5. AVIATION An airplane is flying with an airspeed of 500 miles per hour on a heading due north. If a 50-mile per hour wind is blowing at a bearing of 270°, determine the velocity and direction of the plane relative to the ground. 502.49 mph; 44.6 N; 40.1 N b. Find the magnitudes of the horizontal and vertical components of the force. 42° 60 N a. Draw a diagram that shows the resolution of the force Roland exerts into its rectangular components. 4. CONSTRUCTION Roland is pulling a crate of construction materials with a force of 60 Newtons at an angle of 42° with the horizontal. 200 1150 ft at a bearing of 52.1° north of west 3. GROCERY SHOPPING Caroline walks 45° north of west for 1000 feet and then walks 200 feet due north to go grocery shopping. How far and at what north of west quadrant bearing is Caroline from her apartment? 8 / 1. r = 60 meters at a bearing of N45°E Use a ruler and a protractor to draw an arrow diagram for each quantity described. Include a scale on each diagram. 8-1 NAME Answers (Lesson 8-1) Chapter 8 4 150° & A3 PERIOD 4 35 m 20° & 30° 45 m 79.7 m; E25.6°N Glencoe Precalculus b. Find the resulting distance and the direction of her path. 8 / a. Use a ruler and protractor to draw an arrow diagram representing the situation. 6. SKATEBOARDING Meredith is skateboarding along a path 20° north of east for 35 meters. She then changes paths and travels for 45 meters along a path 30° north of east. 119.5 meters; N55.1°W 5. ORIENTEERING In an orienteering competition, Jada walks N70°W for 200 meters. She then walks due east for 90 meters. How far and at what bearing is Jada from her starting point? decrease 4. TRAVEL Karrie is pulling her luggage across the airport floor. She applies a 22-newton force to the handle of the bag when the bag makes a 72-degree angle with the floor. What is the magnitude of the force that moves the luggage straight forward? What effect would it have if Karrie moved the handle closer to the floor, decreasing the angle? 20.9 N; the force would 3. CANOEING A person in a canoe wants to cross a 65-foot-wide river. He begins to paddle straight across the river at 1.2 m/s while a current is flowing perpendicular to the canoe. If the resulting velocity of the canoe is 3.2 m/s, what is the speed of the current to the nearest tenth? 3.0 m/s DATE 10/23/09 11:27:09 AM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Glencoe Precalculus 005_032_PCCRMC08_893809.indd 8 Chapter 8 No. Sample answer: If you use the triangle method of vector addition, the resultant will be in the same position regardless of the individual angles. c. Would changing the angle of the tractors affect the magnitude of the resulting force if the angle between the tractors remained 40°? Explain. b. What is the resulting force on the tree stump? 3293 N 3288.9 N; 171 N a. What is the sum of the horizontal components of the tractors? What is the sum of the vertical components? 1500 N 20° 20° 2000 N 2. FARMING Two tractors are removing a tree stump as shown. One tractor pulls with a force of 2000 newtons, and the other tractor pulls with a force of 1500 newtons. The angle between the two tractors is 40°. 1 cm: 50 km 8 / 8 Introduction to Vectors Word Problem Practice 1. SAILING A captain sails a boat east for 200 kilometers at a bearing of 150°. Use a ruler and protractor to draw an arrow diagram for the quantities described. Include a scale on the diagram. 8-1 NAME Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Enrichment DATE PERIOD 180° 150° 70° 80 N 80 N 120 N Answers Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 9 Chapter 8 9 2. MOVING Three men are trying to move a sofa. One man is pushing on the sofa with a force of 40 N at an angle of 50° with the ground. A second man exerts a force of 100 N at 110°, and a third man exerts a force of 10 N at 150°. Find the magnitude and direction of the resultant force. 130.7 N; 97.7° 1. DOGS Three dogs are pulling a wagon. One dog acts with 40 N at 50° on the wagon. The second dog acts with 100 N at 110°. The third dog acts with 10 N at 150°. Find the magnitude and direction of the resultant force. 131 N; 98° Find the magnitude and direction of the resultant force acting on each object. r Lesson 8-1 3/25/09 10:04:51 PM Glencoe Precalculus a Now add the resulting vector to the 120 N vector. The resultant force is 219 N at a direction of 145°. 100 N a Add the 80 N vector and the 100 N vector first. First, add two of the vectors. The order in which the vectors are added does not matter. 120 N 100 N Example CONSTRUCTION Kendra is pulling on a box with a force of 80 newtons at an angle of 70° with the ground at the same time that Kyle is pulling on the box with a force of 100 newtons at an angle of 150° with the ground. A third force of 120 N acts at an angle of 180°. Find the magnitude and direction of the resultant force acting on the box. Three or more forces may work on an object at one time. Each of these forces can be represented by a vector. To find the resultant vector that acts upon the object, you can add the individual vectors two at a time. More Than Two Forces Acting on an Object 8-1 NAME Answers (Lesson 8-1) Vectors in the Coordinate Plane Study Guide and Intervention DATE (-4 - 2) 2 + [2 - (-3)] 2 √ A4 Subtract. (x1, y1) = (2, −3) and (x2, y2) = (−4, 2) Component form = 〈4 + (-1), 2 + 3〉 or 〈3, 5〉 Vector addition = 〈11, 9〉 −4 −2 2 0 2 y X 4 x 2. A(-15, 0), B(7, -19) 〈22, -19〉, 13 √ 5 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 10 10 Glencoe Precalculus 6. f - 2(g + 2h) 〈-40, -32〉 5. 2g + h 〈47, 39〉 Chapter 8 4. 8g - 2f + 3h 〈181, 163〉 3. f - g 〈-20, -23〉 Find each of the following for f = 〈4, -2〉, g = 〈24, 21〉, and h = 〈-1, -3〉. 1. A(12, 41), B(52, 33) 〈40, -8〉, 8 √ 26 ⎯⎯⎯ with the Find the component form and magnitude of the vector AB given initial and terminal points. Exercises Scalar multiplication Substitute. Vector addition Substitute. = 〈12, 6〉 + 〈-1, 3〉 3s + t = 3〈4, 2〉 + 〈-1, 3〉 b. 3s + t −4 −2 Y 4 Find each of the following for s = 〈4, 2〉 and t = 〈-1, 3〉. s + t = 〈4, 2〉 + 〈-1, 3〉 a. s + t Example 2 ⎯⎯⎯ = 〈x2 - x1, y2 - y1〉 XY = 〈-4 - 2, 2 - (-3)〉 = 〈-6, 5〉 ⎯⎯⎯as an ordered pair. Represent XY = √ 61 or about 7.8 units (-6) 2 + 5 2 = √ = ⎪XY ⎯⎯⎯⎥ = √ (x2 - x1)2 + (y2 - y1)2 Example 1 ⎯⎯⎯ with initial point X(2, −3) and Find the magnitude of XY terminal point Y(-4, 2). ⎯⎯⎯ using the Distance Formula. Determine the magnitude of XY The magnitude of a vector in the coordinate plane is found using the Distance Formula. PERIOD 10/24/09 10:52:30 AM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 Vectors in the Corrdinate Plane 8-2 NAME DATE (continued) PERIOD 〉 〈 〉 ⎯⎯⎯ be the vector with initial point M(2, 2) and terminal Let MP Scalar multiplication Simplify. 〈a, b〉 = ai + bj Component form -3 〈−45 , − 5 〉 2. w = 〈10, 25〉 29 2 √ 29 5 √ 29 29 〈−, −〉 4. M(0, 6), N(18, 4) 18i - 2j Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 11 Chapter 8 7. -4i + 2j 153.4° 8. 〈2, 17〉 83.3° 11 Lesson 8-2 10/23/09 11:43:12 AM Glencoe Precalculus 6. |v| = 5, θ = 95° 〈-0.44, 5.0〉 Find the direction angle of each vector to the nearest tenth. 5. |v| = 18, θ = 240° 〈-9, -15.6〉 Find the component form of v with the given magnitude and direction angle. 3. M(2, 8), N(-5, -3) -7i - 11j ⎯⎯⎯⎯ be the vector with the given initial and terminal points. Write MN ⎯⎯⎯⎯ Let MN as a linear combination of the vectors i and j. 1. p = 〈4, -3〉 Find a unit vector u with the same direction as the given vector. Exercises ⎯⎯⎯⎯ = 〈3, 2〉 MP = 3i + 2j ⎯⎯⎯⎯ = 〈x2 - x1, y2 - y1〉 MP Component form = 〈5 - 2, 4 - 2〉 or 〈3, 2〉 (x1, y1) = (2, 2) and (x2, y2) = (5, 4) Then rewrite the vector as a linear combination of the standard unit vectors. ⎯⎯⎯ as a linear combination of the vectors i and j. point P(5, 4). Write MP ⎯⎯⎯⎯. First, find the component form of MP Example 2 -4 -1 = − , − or √ 17 17 √ 〈 √ 17 -4 √ 17 - √ 17 −, − 17 17 a2 + b2 ⎪〈a, b〉⎥ = √ 1 = − 〈-4, -1〉 √ (-4)2 + (-1)2 1 =− 〈-4, -1〉 Substitute. Unit vector with the same direction as v Find a unit vector u with the same direction as v = 〈-4, -1〉. 1 = − 〈-4, -1〉 ⎪〈-4, -1〉⎥ 1 u=− v ⎪v⎥ Example 1 A vector that has a magnitude of 1 unit is called a unit vector. A unit vector in the direction of the positive x-axis is denoted as i = 〈1, 0〉, and a unit vector in the direction of the positive y-axis is denoted as j = 〈0, 1〉. Vectors can be written as linear combinations of unit vectors by first writing the vector as an ordered pair and then writing it as a sum of the vectors i and j. Vectors in the Coordinate Plane Study Guide and Intervention Unit Vectors 8-2 NAME Answers (Lesson 8-2) Chapter 8 Vectors in the Coordinate Plane Practice DATE PERIOD 10 〈1, -3〉; √ 2. A(4, -2), B(5, -5) A5 √ 5 2 √5 5 5 〈- −, −〉 9. v = 〈-8, -2〉 4 √ 17 17 √ 17 17 〈- −, - −〉 146 〈11, 5〉; √ 3. A(-3, -6), B(8, -1) 13. D(2, 1), E(3, 7) i + 6j 12. D(4, 6), E(-5, -2) -9i − 8j 〈8.9, 8.0〉 15. |v| = 8, θ = 132° 〈−5.4, 5.9〉 12 Glencoe Precalculus 3/23/09 5:44:04 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Glencoe Precalculus 005_032_PCCRMC08_893809.indd 12 Chapter 8 295.62 N 16. GARDENING Anne and Henry are lifting a stone statue and moving it to a new location in their garden. Anne is pushing the statue with a force of 120 newtons at a 60° angle with the horizontal while Henry is pulling the statue with a force of 180 newtons at a 40° angle with the horizontal. What is the magnitude of the combined force they exert on the statue? 14. |v| = 12, θ = 42° Find the component form of v with the given magnitude and direction angle. 11. D(-4, 3), E(5, -2) 9i − 5j 10. D(4, -5), E(6, -7) 2i − 2j ⎯⎯⎯ be the vector with the given initial and terminal points. Write DE ⎯⎯⎯ Let DE as a linear combination of the vectors i and j. 8. v = 〈-3, 6〉 Find a unit vector u with the same direction as v. 〈-21, 28〉 7. 5w - 3v 6. 4v + 3w 〈-1, 11〉 〈-7, 7〉 5. w - 2v 〈6, -3〉 4. 3v Find each of the following for v = 〈2, -1〉 and w = 〈-3, 5〉. 10 〈-3, -1〉; √ 1. A(2, 4), B(-1, 3) ⎯⎯⎯ with the given initial and Find the component form and magnitude of AB terminal points. 8-2 NAME Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 48° 3. HIKING Amel is hiking in the forest. He hikes 2 miles west and then hikes 3.4 miles north. If he would have hiked diagonally to reach the same ending point, how much shorter would his hike have been? 1.5 mi 3.3i + 5.25j 2. TRANSPORTATION Jordyn is riding the bus to school. The bus travels north for 4.5 miles, east for 2 miles, and then 30° north of east for 1.5 miles. Express Jordyn’s commute as a linear combination of unit vectors i and j. horizontal b. What is the resultant direction of the javelin? 42.5° with the a. What is the resultant speed of the javelin? 30.8 m/s Answers Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 13 Chapter 8 DATE 13 PERIOD start end θ Lesson 8-2 10/23/09 11:44:15 AM Glencoe Precalculus c. If Walter wants to land directly in front of his starting point, at what angle with respect to the shore should he kayak? 122° b. At what angle will Walter be moving with respect to the shore? 58° a. What is the resultant velocity of the kayak? 4.7 m/s 4 m/s 2.5 m/s 6. KAYAKING Walter is kayaking across a river that has a current of 2.5 meters per second. He is paddling at a rate of 4 meters per second perpendicular to the shore. 427 mph 5. FLYING To reach a destination, a pilot is plotting a course that will result in a velocity of 450 miles per hour at an angle of 30° north of west. The wind is blowing 50 miles per hour to the north. Find the direction and speed the pilot should set to achieve the desired resultant. 24.2° north of west, 4. AIRPLANES An airplane is traveling 300 kilometers per hour due east. A wind is blowing 35 kilometers per hour 75° south of west. What is the resulting speed of the airplane? 292.9 km/h Vectors in the Coordinate Plane Word Problem Practice 1. TRACK Monica is throwing the javelin in a track meet. While running at 4 meters per second, she throws the javelin with a velocity of 28 meters per second at an angle of 48°. 8-2 NAME Answers (Lesson 8-2) Enrichment PERIOD 40° 25 N A6 -19.2 N 40° 25 N -68.6 N 19.2 N 52.5 N 52.5 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 14 Chapter 8 14 Glencoe Precalculus 2. What is the coefficient of friction for a person pushing a 25-kilogram box across a carpeted floor with a force of 75 newtons if the force is being applied at 25°? 0.32 1. What is the coefficient of friction for a person pulling a 41-kilogram child on a sled if the angle of the rope is 45° and the force of the pull is 50 newtons? 0.10 Exercises Therefore, the coefficient of friction is 0.37. 16.1 N ≈ 19.2 x-component ≈ 16.1 y-component Force due to gravity = mass × acceleration due to gravity 7(-9.8) = -68.6 n = 68.6 - 16.1 = 52.5 Normal force 19.2 μ=− about 0.37 Coefficient of friction x = 25 cos 40° y = 25 sin 40° A force diagram can be used to represent this situation. Calculate the x-component and the y-component of the 25-newton force. Because the wagon is moving at a constant velocity, the force of friction has to be equal to, but opposite the x-component. The force of gravity is balanced by the sum of the y-component and the normal force. Consider a person pulling a 7-kilogram wagon with a constant velocity as shown in the diagram. The person is pulling with a force of 25 newtons and the wagon handle makes a 40° angle with the horizontal. What is the coefficient of friction for the situation? Example According to Newton’s first law of motion, if an object is moving with constant velocity, then all the forces in the system are balanced. If the object is not moving at a constant velocity, then the forces are unbalanced. So, if a person is pushing on an object and the object is moving at a constant velocity, the force of the person pushing on the object is balanced by the force of friction. The coefficient of friction μ (pronounced “mu”) is the ratio of the force of friction between two surfaces and the force pushing the surfaces together. When an object is resting on the ground, the force pushing them together is found by multiplying the mass (in kilograms) by acceleration due to gravity, -9.8 m/s2. The normal force n is the force of the ground pushing back up on the object. DATE 10/23/09 11:52:19 AM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 Friction and the Normal Force 8-2 NAME DATE Simplify and solve for θ. -54, not orthogonal 2. u = -8i + 5j, v = 3i −6j 4 √ 10 3 √ 10 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 15 Chapter 8 179.3° 5. u = 〈-3, -5〉, v = 〈7, 12〉 15 39.5° 6. u = 13i - 5j, v = 6i + 2j Find the angle θ between u and v to the nearest tenth of a degree. 4. c = 〈−12, 4〉 3. a = 〈9, 3〉 Use the dot product to find the magnitude of the given vector. 0, orthogonal 1. u = 〈2, 4〉, v = 〈−12, 6〉 Lesson 8-3 10/23/09 11:58:37 AM Glencoe Precalculus Find the dot product of u and v. Then determine if u and v are orthogonal. Exercises The measure of the angle between u and v is about 112°. -10 + 3 √ 26 √ 13 Evaluate. θ = cos −1 − or about 112° u = 〈5, 1〉 and v = 〈−2, 3〉 -10 + 3 cos θ = − √ 26 √ 13 Angle between two vectors 〈5, 1〉 · 〈-2, 3〉 cos θ = − |〈5, 1〉| |〈-2, 3〉| |u| |v| u·v cos θ = − and v = 〈−2, 3〉. Find the angle θ between vectors u and v if u = 〈5, 1〉 u · v = 4(8) + 5(-6) =2 Since u · v ≠ 0, u and v are not orthogonal. u · v = 5(−3) + 1(15) =0 Since u · v = 0, u and v are orthogonal. Example 2 b. u = 〈4, 5〉, v = 〈8, -6〉 a. u = 〈5, 1〉, v = 〈-3, 15〉 Example 1 Find the dot product of u and v. Then determine if u and v are orthogonal. |a| |b| PERIOD The dot product of a = 〈a 1, a 2〉 and b = 〈b 1, b 2〉 is defined as a · b = a 1b 1 + a 2b 2. The vectors a and b are orthogonal if and only if a · b = 0. a·b If θ is the angle between nonzero vectors a and b, then cos θ = − . Dot Products and Vector Projections Study Guide and Intervention Dot Product 8-3 NAME Answers (Lesson 8-2 and Lesson 8-3) Chapter 8 DATE Dot Products and Vector Projections Study Guide and Intervention (continued) PERIOD 〈 13 13 〉 A7 13 13 〉 〈 13 13 〉 〈 13 13 〉 9 56 72 7 7 9 , -− ; u = 〈− , -− + − ,− 〈− 65 〉 65 65 〉 〈 65 65 〉 65 3. u = 〈1, 1〉, v = 〈9, -7〉 205 205 〉 16 1508 696 + -− ,− 〈 286 132 286 132 , -− ; u = 〈- − , -− 〈- − 205 205 〉 205 〉 205 Glencoe Precalculus 3/23/09 5:44:23 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Glencoe Precalculus 005_032_PCCRMC08_893809.indd 16 Chapter 8 5. u = −8i + 2j, v = 6i + 13j 180 15 23 276 180 15 , − ; u = 〈− ,− + − , -− 〈− 29 29 〉 〈 29 29 〉 29 29 〉 205 205 328 295 472 328 + -− , −〉 , -− ; u = 〈- − , -− 〈- − 89 89 〉 89 〉 〈 89 89 89 2. u = 〈−7, 3〉, v = 〈8, 5〉 4. u = 7i - 9j, v = 12i + j 〈−4017 , - −1017 〉; u = 〈−4017 , - −1017 〉 + 〈−1117 , −4417 〉 1. u = 〈3, 2〉, v = 〈-4, 1〉 Find the projection of u onto v. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. Exercises 〈 13 13 〉 4 6 = 〈8, 6〉 − - − ,− 〈 108 72 = 〈−, −〉 13 13 Step 2 Find u − proj v u. 108 72 4 6 4 6 ,− . Therefore, proj v u is - − , − and u = - − ,− + − 13 2 4 6 〈2, -3〉 or - − ,− = -− |〈2, -3〉| =− 〈2, -3〉 2 〈8, 6〉 · 〈2, -3〉 ( |v| ) u·v proj v u = − v 2 Step 1 Find the projection of u onto v. Example Find the projection of u = 〈8, 6〉 onto v = 〈2, −3〉. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. ( |v| ) u·v proj v u = − v. 2 A vector projection is the decomposition of a vector u into two perpendicular parts, w1 and w2, in which one of the parts is parallel to another vector v. When you find the projection of u onto v, you are finding a component of u that is parallel to v. To find the projection of u onto v, use the formula: Vector Projection 8-3 NAME Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Dot Products and Vector Projections Practice DATE PERIOD -11, not orthogonal 2. u = -i + 4j, v = 3i − 2j -2, not orthogonal 3. u = 〈2, 0〉, v = 〈−1, −1〉 6 8 6 8 33 44 , − ; -− ,− + − , -− 〈- − 25 25 〉 〈 25 25 〉 〈 25 25 〉 99 25 75 33 33 99 , -− ; − , -− + − ,− 〈− 2〉 〈2 2 〉 〈2 2〉 2 32 16 12 24 12 24 , − ; -− , − + 〈− ,− 〈- − 5 5〉 5 5〉 〈 5 5〉 Answers Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 17 Chapter 8 17 Lesson 8-3 10/23/09 11:59:46 AM Glencoe Precalculus 12. PHYSICS Janna is using a force of 100 pounds to push a cart up a ramp. The ramp is 6 feet long and is at a 30° angle with the horizontal. How much work is Janna doing in the vertical direction? (Hint: Use the sine ratio and the formula W = F · d.) 300 ft-lb 11. TRANSPORTATION Train A and Train B depart from the same station. The path that train A takes can be represented by 〈33, 12〉. If the path that train B takes can be represented by 〈55, 4〉, find the angle between the pair of vectors. 15.8° 10. u = 〈−2, −1〉, v = 〈−3, 4〉 9. u = 〈62, 21〉, v = 〈−12, 4〉 8. u = 〈4, 8〉, v = 〈−1, 2〉 Find the projection of u onto v. Then write u as the sum of two orthogonal vectors, one of which is the projection of u onto v. 7. u = 5i − 4j, v = 2i + j 65.2° 6. u = 27i + 14j, v = i − 7j 109.3° 5. u = 〈−6, −2〉, v = 〈2, 12〉 117.9° 4. u = 〈−1, 9〉, v = 〈3, 12〉 20.4° Find the angle θ between u and v to the nearest tenth of a degree. 0, orthogonal 1. u = 〈3, 6〉, v = 〈−4, 2〉 Find the dot product of u and v. Then determine if u and v are orthogonal. 8-3 NAME Answers (Lesson 8-3) A8 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 18 Chapter 8 Sample answer: As the angle increases, the force in the direction of the motion decreases; so, the work done decreases. b. Use your results from part a to explain why as the angle increases the work decreases. 1532 J, 0 J a. Determine the amount of work done if the angle of the rope is at 40° with the horizontal; 90° with the horizontal. 3. BOATING Shea is pulling a boat along a dock using a rope. She exerts a force of 200 newtons on the rope and pulls the boat 10 meters. 2. TARGETS Two clay pigeons are thrown at the same time. If the path of the clay pigeons can be represented by the vectors p = 〈42, 58〉 and c = 〈59, 73〉, what was the measure of the angle between the clay pigeons? 3° 13.9 units 18 PERIOD Glencoe Precalculus 6. SCAVENGER HUNT During a scavenger hunt, Alexis and Marty go in different directions. If the path that Alexis takes can be represented by 〈9, 18〉 and the path taken by Marty can be represented by 〈-15, 12〉, who travels the farthest distance? Alexis 60° 5. CARNIVALS A slide at a carnival has an incline of 60°. A 50-pound girl gets part way down the slide and stops. Ignoring the force of friction, what is the magnitude of the force that is required to keep her from sliding down farther? 43.3 pounds 1125 J c. How much work is done by the pilot? 43.2° b. What is the measure of the angle made by the staircase? 11.0 m a. What is the length of the staircase? 4. TRAVELING A pilot is carrying a bag weighing 150 newtons up a flight of stairs. The staircase covers a horizontal distance of 8 meters and a vertical distance 7.5 meters. Dot Products and Vector Projections Word Problem Practice DATE 10/23/09 12:01:26 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 1. SUBMARINES The path of a submarine can be described by the vector v = 〈8, 3〉. If the submarine then changes direction and travels along the vector u = 〈2, 5〉, what is the distance traveled by the submarine? 8-3 NAME Enrichment DATE f(x) -1 a + 2b + c a 0 1 a - 2b + c 2 0 〈0, 1〉 1 〈0, -3〉 2 〈4, -11〉 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 19 Chapter 8 19 a = 〈0, 1, –2〉 b = 〈1, –2, 0〉 c = 〈-2, 0, 1〉 4. f(x) = x 3a - xb + 3c a = 〈1, 1, 1〉 b = 〈3, 2, 1〉 c = 〈0, 1, 2〉 3. f(x) = x 2c + 3xa - 4b a = 〈0, 1, 1〉 b = 〈1, 0, 1〉 c = 〈1, 1, 0〉 2. f(x) = 2x 2a + 3xb - 5c a = 〈1, 1〉 b = 〈2, 3〉 c = 〈3, –1〉 1. f(x) = x 3a - 2x 2b + 3xc 3 2 1 x 0 3 2 1 x 0 1 0 –1 x –2 2 1 0 x –1 f(x) Lesson 8-3 10/23/09 12:02:42 PM Glencoe Precalculus 〈–6, 0, 3〉 〈-7, 3, 1〉 〈-8, 12, -13〉 〈-9, 33, -51〉 f(x) 〈–12, –8, -4〉 〈-9, -4, 1〉 〈-6, 2, 10〉 〈-3, 10, 23〉 f(x) 〈–11, 3, 2〉 〈-8, -3, -1〉 〈-5, -5, 0〉 〈-2, -3, 5〉 f(x) 〈–14, –4〉 〈0, 0〉 〈6, –8〉 〈10, –22〉 For each of the following, complete the table of resulting vectors. -1 〈4, 1〉 -2 〈12, -3〉 x f(x) PERIOD a - 4b + 4c If a = 〈0, 1〉, b = 〈1, 1〉, and c = 〈2, –2〉, the resulting vectors for the values of x are as follows. -2 a + 4b + 4c x Let a, b, and c be fixed vectors. The equation f(x) = a - 2xb + x 2c defines a vector function of x. For the values of x shown, the assigned vectors are given below. Vector Equations 8-3 NAME Answers (Lesson 8-3) Chapter 8 DATE Vectors in Three-Dimensional Space Study Guide and Intervention PERIOD (x2 - x1)2 + (y2 - y1)2 + (z2 - z1)2 √ (x2, y2, z2) = (7, -9, 3) (x1, y1, z1) = (10, 2, -5) and Distance Formula A9 2 1 2 1 2 ≈ (8.5, -3.5, -1) 0 z (3, 2, 1) 2 y (4, -2, -1) x -2 2. (4, −2, -1) 0 z (x1, y1, z1) = (10, 2, -5) and y (x2, y2, z2) = (7, -9, 3) ) ( 12 5 5 2 2 19 2 ) 20 Glencoe Precalculus 3/23/09 5:44:44 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Glencoe Precalculus 005_032_PCCRMC08_893809.indd 20 Chapter 8 4. (-6, -12, -8), (7, -2, -11) 16.67; −, -7, - − ( 3. (8, -3, 9), (2, 8, -4) 18.06; 5, −, − Find the length and midpoint of the segment with the given endpoints. x 1. (3, 2, 1) Plot each point in a three-dimensional coordinate system. Exercises The midpoint is at the coordinates (8.5, -3.5, -1). 1 x +x y +y z +z 10 + 7 2 + (-9) -5 + 3 , − , − ) = ( −, − , − ) (− 2 2 2 2 2 2 Use the Midpoint Formula for points in space. b. The hikers decided to meet at the midpoint between their paths. What are the coordinates of the midpoint? = √(7 - 10)2 + ((-9) - 2)2 + (3 - (-5))2 ≈ 13.93 The hikers are about 14 kilometers apart. AB = Use the Distance Formula for points in space. a. How far apart are the hikers? Example HIKING The location of two hikers are represented by the coordinates (10, 2, -5) and (7, -9, 3), where the coordinates are given in kilometers. Ordered triples, like ordered pairs, can be used to represent vectors. Operations on vectors represented by ordered triples are similar to those on vectors represented by ordered pairs. Coordinates in Three Dimensions 8-4 NAME Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. DATE (continued) PERIOD 〈 √ 3 √ 70 3 √70 70 −, - −, - − 35 70 14 〉 ⎯⎯⎯ AB = 〈6, -3, -5〉 and ⎪ ⎯⎯⎯ AB ⎥ = √ 70 Unit vector in the direction of ⎯⎯⎯ AB ⎯⎯⎯ AB = 〈6, -3, -5〉 (x1, y1, z1) = (-3, 5, 1) and (x2, y2, z2) = (3, 2, −4) Component form of vector 4 9 434 434 17 434 434 217 434 Answers Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 21 Chapter 8 3. 3x + 2y - 4z 〈19, -52, -17〉 21 Lesson 8-4 10/23/09 12:04:32 PM Glencoe Precalculus 4. -6y + 2z 〈-10, 54, -34〉 Find each of the following for x = 3i + 2j - 5k, y = i - 5j + 7k, and z = -2i + 12j + 4k. 3 115 115 √ √ √ , −, − 〉 〈− 115 23 √ √ √ , −, - − 〉 〈− 9 115 115 〈9, 8, 17〉, √ 434 ; 2. A(-1, -4, -7), B(8, 4, 10) 〈18, -10, -6〉, 2 √ 115 ; 1. A(-10, 3, 9), B(8, -7, 3) ⎯⎯⎯ with the given initial Find the component form and magnitude of AB ⎯⎯⎯. and terminal points. Then find a unit vector in the direction of AB Exercises √ 70 = − or 〈6, -3, -5〉 ⎪AB ⎯⎯⎯⎯⎥ ⎯⎯⎯⎯ AB u=− Using this magnitude and component form, find a ⎯⎯⎯⎯. unit vector u in the direction of AB ⎪AB ⎯⎯⎯⎯⎥ = √ 62 + (-3)2 + (-5)2 or √ 70 . ⎯⎯⎯⎯ is Using the component form, the magnitude of AB = 〈3 - (-3), 2 - 5, -4 - 1〉 or 〈6, -3, -5〉 ⎯⎯⎯⎯ = 〈x2 - x1, y2 - y1, z2 - z1〉 AB Example ⎯⎯⎯ with initial Find the component form and magnitude of AB point A(-3, 5, 1) and terminal point B(3, 2, -4). Then find a unit vector in the ⎯⎯⎯. direction of AB Operations on vectors represented by ordered triples are similar to those on vectors represented by ordered pairs. Three-dimensional vectors can be added, subtracted, and multiplied by a scalar in the same ways. In space, a vector v in standard position with a terminal point located at (v1, v2, v3) is denoted by 〈v1, v2, v3〉. Thus, the zero vector is 0 = 〈0, 0, 0〉 and the standard unit vectors are i = 〈1, 0, 0〉, j = 〈0, 1, 0〉, and k = 〈0, 0, 1〉. The component form of v can be expressed as a linear combination of these unit vectors, 〈v1, v2, v3〉 = v1i + v2 j + v3k. Vectors in Three-Dimensional Space Study Guide and Intervention Vectors in Space 8-4 NAME Answers (Lesson 8-4) Vectors in Three-Dimensional Space Practice DATE 0 z y (-3, 4, -1) x (4, 7, 6) y x (3, -2, 6) 4. 〈4, -2, 6〉 x (2, 0, -5) 2. (2, 0, -5) 0 z z y y A10 〈 〉 〈 √ 411 411 11 √ 411 17 √ −, - −, − 411 411 411 411 〈1, -11, 17〉; √ 8. A(6, 8, -5), B(7, -3, 12) 2 2 ) ( 2) 7 √ 445 ; -7, -6, − 10. (-17, -3, 2), (3, -9, 5) 〈-2, -4, 7〉 12. 5v - 2w 〉 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 22 Chapter 8 22 Glencoe Precalculus 13. PHYSICS Suppose that the force acting on an object can be expressed by the vector 〈85, 35, 110〉, where each measure in the ordered triple represents the force in pounds. What is the magnitude of this force? about 143 lb 〈8, -12, 14〉 11. v + w Find each of the following for v = 〈2, -4, 5〉 and w = 〈6, -8, 9〉. 1 11 √ 158 ; - − , −, -4 ( 9. (3, 4, -9), (-4, 7, 1) Find the length and midpoint of the segment with the given endpoints. 419 419 3 √ 419 17 √ 11 √ −, - −, - − 419 419 419 419 〈11, -3, -17〉; √ 7. A(-4, 5, 8), B(7, 2, -9) 9 √ 91 91 〈−, −, - − 〉 〈- −, −, − 〉 3 √ 91 √ 91 91 91 91 〈3, 1, -9〉; √ 17 〈-6, 4, 4〉; 2 √ 3 √ 17 2 √ 17 2 √ 17 17 17 17 6. A(4, 0, 6), B(7, 1, -3) 5. A(2, 1, 3), B(-4, 5, 7) ⎯⎯⎯⎯ with the given initial Find the component form and magnitude of AB ⎯⎯⎯⎯. and terminal points. Then find a unit vector in the direction of AB z 3. 〈4, 7, 6〉 Locate and graph each vector in space. x 1. (-3, 4, -1) PERIOD 3/23/09 5:44:57 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 Plot each point in a three-dimensional coordinate system. 8-4 NAME 18 ft 3 ft Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 23 Chapter 8 c. If the bale elevator is only 27 feet long and the only thing that can be changed is the 18 feet that the farmer is away from the opening, to the nearest foot, how close does he need to be in order to still have two feet past the opening? 15 ft b. If the bale elevator needs to be 2 feet past the opening, to the nearest foot, how long does the bale elevator have to be? 30 ft a. To the nearest foot, how long should the bale elevator be in order to reach the opening? 28 ft 24 ft 3 ft 2. FARMING A farmer is using a bale elevator to move bales of hay into the loft of his barn. The opening of the loft door is 18 feet away from where the bales will be loaded onto the bale elevator, 3 feet to the right of where the bales will be loaded, and 24 feet above the ground. The opening can be represented by the point (18, 3, 24). The bales will be loaded onto the elevator 3 feet above the ground. This can be represented by (0, 0, 3). 487.35 ft) 2 ft DATE 23 PERIOD (1, - −12 , 6) Lesson 8-4 10/23/09 12:05:29 PM Glencoe Precalculus 6. BIKING A youth group is hosting a team bike race with pairs of competitors. Each team will switch riders half-way through the race. If the starting point can be represented by (0, 0, 3) and the ending point can be represented by the point (2, -1, 9), at what point will the cyclists trade? 0.62 mi 5. ZIP-LINES A resort in Colorado has a series of zip-lines that tourists can take to travel through some wooded areas. The platform of the first zip-line is represented by the point (1.5, 0.5, 0.4) and a second platform can be represented by the point (1.8, 1, 0.2). How long is the zip-line if the coordinates are in miles? -4.70i + 2.98j - 2.72k 4. ROBOTICS An underwater robot is being used to explore parts of the ocean floor. The robot is diving due north at 3 m/s at an angle of 65˚ with the surface of the water. If the current is flowing at 5 m/s at an angle of 20˚ north of west, what is the vector that represents the resultant velocity of the underwater robot? Let i point east, j point north, and k point up. b. Are they in violation of the regulation? yes 2268 ft a. How far apart are the planes? 3. AIRPLANE Safety regulations require airplanes to be at least a half mile apart when they are in the air. Two airplanes near an airport can be represented by the points (300, 455, 2800) and (-250, 400, 5000), where the coordinates are given in feet. Vectors in Three-Dimensional Space Word Problem Practice 1. TRAVELING A family from Des Moines, Iowa, is driving to Tampa, Florida. According to the car’s GPS, Des Moines is at (93.65˚, 41.53˚, 955 ft) and Tampa is at (82.53˚, 27.97˚, 19.7 ft). Determine the longitude, latitude, and altitude of the halfway point. (88.09˚, 34.75˚, 8-4 NAME Answers (Lesson 8-4) Chapter 8 Enrichment DATE PERIOD r+s-t A11 7 7 2 24 Glencoe Precalculus 10/23/09 12:06:12 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Glencoe Precalculus 005_032_PCCRMC08_893809.indd 24 Chapter 8 2 3 1 v = -− u+− z 3. v = 〈1, -1, 2〉, u = 〈1, 2, -1〉, w = 〈2, 2, 1〉, and z = 〈1, 0, 1〉 7 23 8 1 v= − u-− w+− z 2. v = 〈5, -2, 0〉, u = 〈1, -2, 3〉, w = 〈-1, 0, 1〉, and z = 〈4, 2, -1〉 v = -5u - w + 3z 1. v = 〈-6, -2, 2〉, u = 〈1, 1, 0〉, w = 〈1, 0, 1〉, and z = 〈0, 1, 1〉 Write each vector as a linear combination of the vectors u, w, and z. Solving the system of equations yields the solution r = 0, s = 1, and t = 2. So, v = w + 2z. 3=r+s+t -4 = 3r - 2s - t -1 = r + s - t ) r+s+t 〈-1, -4, 3〉 = r 〈1, 3, 1〉 + s 〈1, -2, 1〉 + t 〈-1, -1, 1〉 = 3r - 2s - t ( Example Write the vector v = 〈-1, -4, 3〉 as a linear combination of the vectors u = 〈1, 3, 1〉, w = 〈1, -2, 1〉, and z = 〈-1, -1, 1〉. Every vector v ∈ v3 can be written as a linear combination of any three nonparallel vectors. The three nonparallel vectors, which must be linearly independent, are said to form a basis for v3, which contains all vectors having 1 column and 3 rows. The expression v = ru + sw + tz, is the sum of three vectors each multiplied by a scalar, and is called a linear combination of the vectors u, w, and z. Basis Vectors in Three-Dimensional Space 8-4 NAME Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Graphing Calculator Activity DATE PERIOD Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Answers 005_032_PCCRMC08_893809.indd 25 Chapter 8 a reflection in the xy-plane 1. Find the reflected pyramid above when you use the transformation matrix B below. Describe the result. ⎡1 0 0⎤ ⎢ B= 0 1 0 ⎢ 0 -1 0 ⎦ ⎣ Exercises 25 See students’ work. ⎡-1 0 0⎤ B = ⎢ 0 1 0 ⎢ ⎣ 0 0 1⎦ Lesson 8-4 3/23/09 5:45:14 PM Glencoe Precalculus 2. Find the transformation matrix to reflect over the yz-plane. Check your answer by applying it to the pyramid above. To find the reflected image, find BA. Verify that your answer is correct by graphing the coordinates. To reflect the image over the xz-plane, use the transformation matrix B. ⎡ 1 0 0⎤ ⎢ B = 0 -1 0 ⎢ ⎣0 0 1⎦ Enter B into a graphing calculator. Enter the vertex matrix into a graphing calculator. A B C D E x ⎡-2 2 2 -2 0⎤ ⎢ The vertex matrix for the pyramid is y -2 -2 2 2 0 . ⎢ z ⎣-2 -2 -2 -2 2⎦ Vectors can be used to translate figures in space, and matrix multiplication can be used to transform figures in space. A vertex matrix is a matrix whose columns are the coordinates of the vertices of the figure with the x-coordinate represented by the first row, the y-coordinate represented by the second row, and the z-coordinate represented by the third row. Consider the pyramid shown at the right. z Use the coordinates of the vertices of the pyramid to create a vertex matrix. & A(-2, -2, -2) B(2, -2, -2) 0 " % y C(2, 2, -2) # $ D(-2, 2, -2) x E(0, 0, 2) Vector Transformations with Matrices 8-4 NAME Answers (Lesson 8-4) PERIOD Dot and Cross Products of Vectors in Space Study Guide and Intervention DATE A12 0, orthogonal 4. u = 3i + 6j - 3k, v = -5i - 2j - 9k 2, not orthogonal 2. u = 〈-2, -4, -6〉, v = 〈-3, 7, -4〉 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 26 Chapter 8 90.5° 7. u = -4i + 5j - 3k, v = -8i - 12j - 9k 80.0° 5. u = 〈5, -22, 9〉, v = 〈14, 2, 4〉 26 36.8° Glencoe Precalculus 8. u = i + 2j - k, v = -i + 4j - 3k 41.3° 6. u = 〈4, -5, 7〉, v = 〈11, -8, 2〉 Find the angle θ between vectors u and v to the nearest tenth of a degree. -10, not orthogonal 3. u = 〈4, -3, 8〉, v = 〈2, -2, -3〉 35; not orthogonal 1. u = 〈3, -2, 9〉, v = 〈1, 2, 4〉 Find the dot product of u and v. Then determine if u and v are orthogonal. Exercises The measure of the angle between u and v is about 82.3°. 89.5 Simplify and solve for θ. Evaluate the dot product and magnitude. 12 cos θ = − √ 89 √ 90 12 θ = cos -1 − or about 82.3° u = 〈4, 8, -3〉 and v = 〈9, -3, 0〉 〈4, 8, -3〉·〈9, -3, 0〉 cos θ = −− ⎪〈4, 8, -3〉⎥ ⎪〈9, -3, 0〉⎥ Example 2 Find the angle θ between vectors u and v if u = 〈4, 8, -3〉 and v = 〈9, −3, 0〉. u·v cos θ = − Angle between two vectors ⎪u⎥ ⎪v⎥ Example 1 Find the dot product of u and v. Then determine if u and v are orthogonal. b. u = 〈3, −2, 1〉, v = 〈4, 5, −1〉 a. u = 〈-3, 1, 0〉, v = 〈2, 6, 4〉 u · v = u1v1 + u2v2 + u3v3 u · v = u1v1 + u2v2 + u3v3 = 3(4) + (−2)(5) + 1(−1) = −3(2) + 1(6) + 0(4) = 12 + (−10) -1 or 1 = −6 + 6 + 0 or 0 Since u · v ≠ 0, u and v are not orthogonal. Since u · v = 0, u and v are orthogonal. ⎪a⎥ ⎪b⎥ 10/23/09 12:06:50 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 Dot Products in Space The dot product of two vectors in space is an extension of the dot product of two vectors in a plane. Similarly, the dot product of two vectors is a scalar. The dot product of a = 〈a1, a2, a3〉 and b = 〈b1, b2, b3〉 is defined as a · b = a1b1 + a2b2 + a3b3. The vectors a and b are orthogonal if and only if a · b = 0. As with vectors in a plane, if θ is the angle between nonzero vectors a and b, then a·b cos θ = − . 8-5 NAME (continued) PERIOD Dot and Cross Products of Vectors in Space Study Guide and Intervention DATE Simplify. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 27 Chapter 8 27 Lesson 8-5 10/23/09 12:17:32 PM Glencoe Precalculus -8i - 28j + 12k; 〈-8, -28, 12〉 〈5, 2, 8〉 = -8(5) + (-28)(2) + 12(8) = 0; 〈-8, -28, 12〉 〈-1, 2, 4〉 = -8(-1) + (-28)(2) + 12(4) = 0 2. u = 〈5, 2, 8〉, v = 〈-1, 2, 4〉 -14i + 2j - 22k; 〈-14, 2, -22〉 〈2, 3, -1〉 = -14(2) + 2(3) + (-22)(-1) = 0; 〈-14, 2, -22〉 〈6, -2, -4〉 = -14(6) + 2(-2) + (-22)(-4) = 0 1. u = 〈2, 3, -1〉, v = 〈6, -2, -4〉 Find the cross product of u and v. Then show that u × v is orthogonal to both u and v. Exercises = 11i or 〈11, 0, 0〉 Component form To show that u × v is orthogonal to both u and v, find the dot product of u × v with u and u × v with v. (u × v) · u (u × v) · v = 〈11, 0, 0〉 · 〈0, 4, 1〉 = 〈11, 0, 0〉 · 〈0, 1, 3〉 = 11(0) + 0(4) + 0(1) = 11(0) + 0(1) + 0(3) =0+0+0 =0+0+0 =0 =0 Because both dot products are zero, the vectors are orthogonal. = 11i - 0j + 0k ⎪ ⎥ ⎪ ⎥ ⎪ ⎥ ⎪ ⎥ Example Find the cross product of u = 〈0, 4, 1〉and v = 〈0, 1, 3〉. Then show that u × v is orthogonal to both u and v. i j k u×v= 0 4 1 u = 0i + 4j + k and v = 0i + j + 3k 0 1 3 0 4 0 1 4 1 = ij+ k Determinant of a 3 × 3 matrix 1 3 0 1 0 3 = (12 - 1)i − (0 - 0) j + (0 − 0)k Determinants of 2 × 2 matrices If two vectors have the same initial point and form the sides of a parallelogram, the magnitude of the cross product will give you the area of the parallelogram. If three vectors have the same initial point and form adjacent edges of a parallelepiped, then the absolute value of the triple scalar product gives the volume. To find the triple scalar product, use the same matrix set up that is used for cross products, but i, j, and k are replaced by the third vector. a × b = (a2b3 - a3b2)i - (a1b3 - a3b1)j + (a1b2 - a2b1)k. If a = a1i + a2j + a3k and b = b1i + b2j + b3k, the cross product of a and b is the vector Cross Product of Vectors in Space Cross Products Unlike the dot product, the cross product of two vectors is a vector. This vector does not lie in the plane of the given vectors but is perpendicular to the plane containing the two vectors. 8-5 NAME Answers (Lesson 8-5) Chapter 8 PERIOD Dot and Cross Products of Vectors in Space Practice DATE 3; not orthogonal 2. 〈-4, -1, 1〉 · 〈1, -3, 4〉 3. 〈0, 0, 1〉 · 〈1, -2, 0〉 0; orthogonal about 96.9° 5. u = 〈3, -2, 1〉, v = 〈-4, -2, 5〉 about 51.3° 6. u = 〈2, -4, 4〉, v = 〈-2, -1, 6〉 A13 〈1, 4, -7〉; 〈1, 4, -7〉 · 〈4, -1, 0〉 = (1)(4) + (4) (-1) + (-7)(0) = 0; 〈1, 4, -7〉 · 〈5, -3, -1〉 = (1)(5) + (4)(-3) + (-7)(-1) = 0 74.2 units2 12. u = 〈2, 0, -8〉, v = 〈-3, -8, -5〉 28 Glencoe Precalculus 10/23/09 12:18:59 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Glencoe Precalculus 005_032_PCCRMC08_893809.indd 28 Chapter 8 8.2 newton meters 14. TOOLS A mechanic applies a force of 35 newtons straight down to a ratchet that is 0.25 meter long. What is the magnitude of the torque when the handle makes a 20° angle above the horizontal? 643 units3 13. Find the volume of the parallelepiped with adjacent edges represented by the vectors 〈3, -2, 9〉, 〈6, -2, -7〉, and 〈-8, -5, -2〉. 62.4 units2 11. u = 〈9, 4, 2〉, v = 〈6, -4, 2〉 Find the area of the parallelogram with adjacent sides u and v. 〈7, 1, -11〉; 〈7, 1, -11〉 · 〈3, 1, 2〉 = (7)(3) + (1)(1) + (-11)(2) = 0; 〈7, 1, -11〉 · 〈2, -3, 1〉 = (7)(2) + (1)(-3) + (-11)(1) = 0 10. 〈4, -1, 0〉 × 〈5, -3, -1〉 = (27)(3) + 3(1) + (14)(-6) = 0; 〈27, 3, 14〉 · 〈-2, 4, 3〉 = (27)(-2) + (3)(4) + (14)(3) = 0 9. 〈3, 1, 2〉 × 〈2, -3, 1〉 〈27, 3, 14〉; 〈27, 3, 14〉 · 〈3, 1, -6〉 = -3(1) + (-3)(3) + (3)(4) = 0; 〈-3, -3, 3〉 · 〈-1, 0, -1〉 = (-3)(-1) + (-3)(0) + 3(-1) = 0 8. 〈3, 1, -6〉 × 〈-2, 4, 3〉 〈-3, -3, 3〉; 〈-3, -3, 3〉 · 〈1, 3, 4〉 7. 〈1, 3, 4〉 × 〈-1, 0, -1〉 Find the cross product of u and v. Then show that u × v is orthogonal to both u and v. about 154.9° 4. u = 〈1, -2, 1〉, v = 〈0, 3, -2〉 Find the angle θ between vectors u and v to the nearest tenth of a degree. -9; not orthogonal 1. 〈-2, 0, 1〉 · 〈3, 2, -3〉 Find the dot product of u and v. Then determine if u and v are orthogonal. 8-5 NAME Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. v = 〈-9, 13, 12〉. What is the surface area of the sculpture? 1802 units2 4. SCULPTURE A parallelepiped sculpture is being created. When the sculpture is set, three adjacent edges can be represented by the vectors t = 〈15, 12, 10〉, u = 〈13, -8, -5〉, and 3. MIRROR Two adjacent edges of a mirror in a dressing room are represented by the vectors 〈3, 4, 2〉 and 〈-4, 4, 3〉. What is the area of the mirror? 33 units2 from the axis of rotation as possible 2. REVOLVING DOOR Erica is standing in a revolving door that is not moving. If Erica wants to produce just enough torque to make the door rotate but wants to apply the least amount of force, where should she push on the door with respect to the axis of rotation? as far away Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 29 Answers Chapter 8 DATE PERIOD 29 〈9, -21, 30〉 Lesson 8-5 10/29/09 12:30:46 PM Glencoe Precalculus d. If the velocity of the rockets remains constant, what vectors would represent the rockets at 3 seconds? 〈9, 18, 36〉, c. What is the measure of the angle between the two rockets? 59.8° b. What vector represents the path of the second rocket? 〈3, -7, 10〉 a. What vector represents the path of the first rocket? 〈3, 6, 12〉 6. ROCKETS Two rockets are launched simultaneously. The first rocket starts at the point (0, 1, 0) and after 1 second is at the point (3, 7, 12). The second rocket starts at the point (0, -1, 0) and after 1 second is at the point (3, -8, 10). 60° 9 5. BICYCLING A cyclist applies a force straight down on a bicycle pedal, as shown in the diagram. The length to the pedal’s axle is 0.2 meter and the angle created with the vertical is 60°. The magnitude of the torque is 150 newton meters. Find the force applied to the pedal. 866 N Dot and Cross Products of Vectors in Space Word Problem Practice 1. MECHANIC A mechanic is setting the timing of an engine. He is using a ratchet to turn the crankshaft. The ratchet is 0.5 meter long and the mechanic applies 22 newtons of force straight down on the handle when the handle is at a 25° angle with the horizontal. What is the magnitude of the torque? 10.0 N-m 8-5 NAME Answers (Lesson 8-5) Enrichment PERIOD A14 2 Glencoe Precalculus 005_032_PCCRMC08_893809.indd 30 Chapter 8 no 5. 〈2, -4, 6〉, 〈3, -1, 2〉, 〈-6, 8, 10〉 no 3. 〈1, 1, 1〉, 〈-1, 0, 1〉, 〈1, -1, -1〉 yes; Sample answer: 〈-2, 6〉 + 2〈1, -3〉 = 〈0, 0〉 1. 〈-2, 6〉, 〈1, -3〉 30 no 4 〉 Glencoe Precalculus 9 6. 〈1, -2, 0〉, 〈2, 0, 3〉, -1, 1, − 〈 yes; Sample answer: 2〈1, 1, 1〉 - 〈-1, 0, 1〉 + 〈-3, -2, -1〉 = 〈0, 0, 0〉 4. 〈1, 1, 1〉, 〈-1, 0, 1〉, 〈-3, -2, -1〉 yes; Sample answer: 2〈3, 6〉 - 3〈2, 4〉 = 〈0, 0〉 2. 〈3, 6〉, 〈2, 4〉 Determine whether the given vectors are linearly dependent. Write yes or no. If yes, give a linear combination that yields a zero vector. dependent. 〈-1, 2, 1〉 + 〈1, -1, 2〉 + −1 〈0, -2, -6〉 = 〈0, 0, 0〉, so the three vectors are linearly 2 1 Hence, one solution is a = 1, b = 1, and c = − . The above system does not have a unique solution. Any solution must satisfy the conditions that a = b = 2c. -a + b =0 2a - b - 2c = 0 a + 2b - 6c = 0 Solve a〈-1, 2, 1〉 + b〈1, -1, 2〉 + c〈0, -2, -6〉 = 〈0, 0, 0〉. Example Are the vectors 〈-1, 2, 1〉, 〈1, -1, 2〉, and 〈0, -2, -6〉 linearly dependent? The zero vector is 〈0, 0〉 in two dimensions and 〈0, 0, 0〉 in three dimensions. A set of vectors is called linearly dependent if and only if there exist scalars, not all zero, such that a linear combination of the vectors yields a zero vector. DATE 3/23/09 5:45:43 PM Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Chapter 8 Linearly Dependent Vectors 8-5 NAME Graphing Calculator Activity DATE PERIOD 2nd ENTER 4 9 3 ENTER ENTER [QUIT] ENTER (–) 1 ENTER 3 (–) ENTER ENTER 3 ENTER ENTER 1 (–) (–) 5 ENTER [MATRIX] ENTER 2nd [MATRIX] ENTER ) ENTER Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 005_032_PCCRMC08_893809.indd 31 Chapter 8 31 Lesson 8-5 3/23/09 5:45:46 PM Glencoe Precalculus 3. The volume of a parallelepiped is 112 cubic units. Three adjacent sides are t = 〈-10, 3, 4〉, u = 〈-8, 7, 3〉, and v = 〈-6, -2, x〉. Is 3, 5, or 9 the correct value of x? 5 u = 〈-31, 3, 22〉, and v = 〈-65, 31, 0〉. 42,936 units3 2. Find the volume of the parallelepiped with adjacent sides t = 〈8, -22, 90〉, u = 〈4, 3, 9〉, and v = 〈2, 3, 1〉. 366 units3 1. Find the volume of the parallelepiped with adjacent sides t = 〈6, -12, -9〉, Exercises The determinant is -350. Volume cannot be negative, so the volume is 350 cubic units. 2nd Now use the MATH menu to calculate the following determinant. ENTER 7 (–) 8 [MATRIX] ENTER 2 2nd Enter the data into the graphing calculator under matrix A. Example Find the volume of a parallelepiped with adjacent sides t = 〈3, -2, 8〉, u = 〈4, 9, -1〉, and v = 〈-1, -5, -7〉. The volume of a parallelepiped with adjacent sides t = 〈t1, t2, t3〉, u = 〈u1, u2, u3〉, and v = 〈v1, v2, v3〉 can be calculated by finding the determinant of the matrix below. ⎡t1 t2 t3 ⎤ ⎢u u u ⎢ 1 2 3 ⎣v1 v2 v3 ⎦ Use Matrices to Find the Volume of Parallelepipeds 8-5 NAME Answers (Lesson 8-5) Chapter 8 Assessment Answer Key (Lessons 8-1 and 8-2) Page 33 A 2. 5.5 cm; 29° 3. 4. (Lesson 8-4) Page 34 12.93 mm, 1.36 mm 1. Quiz 3 1. 2. 3. Page 35 〈5, 0, -12〉; 13 〈-7, -5〉 -15i + 5j 6. D 2. H 3. A 4. H 5. A 11 , 10〉 〈3, - − 3 D 4. 5. 1. 〈3, 11, 10〉 5.9 cm; 187° 5. Mid-Chapter Test 22.7 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. Quiz 4 (Lesson 8-5) 8b. 254.5 lb 〈-15, 20〉 〈21, -24〉 8c. 〈6, -10〉 7. 8a. Quiz 2 (Lesson 8-3) Page 33 1. Answers Quiz 1 〈 76 57 25 25 〈− −〉 6. 〈 〉 u= 1. 〉 −, − ; Page 34 9; not orthogonal 〈18, 38, 25〉; 〈18, 38, 25〉 · 〈5, -5, 4〉 = 0; 〈18, 38, 25〉 · 2. 〈2, 3, -6〉 = 0 149 168 , 25 25 + 76 57 25 25 −, − 7. 86.2° 19.2 N, 16.1 N 3. 84.8° 8. 3. A 54.2° 4. 36 54 ,− 〈- − 13 13 〉 2. 4. 7.9 newton meters 9a. 5. Chapter 8 536.2 J 5. D 9b. A15 〈3.8, 0〉, 〈6.2, 3.3〉 10.5 m/s at 18.2° Glencoe Precalculus Chapter 8 Assessment Answer Key Vocabulary Test Page 36 Form 1 Page 37 1. A 2. H Page 38 11. D 12. J 13. A 14. H 15. A 16. G 17. D 18. J 19. D 20. H 1. component form 2. initial point 3. B 3. orthogonal 4. magnitude 4. 5. parallel vectors 5. A 7. unit vector 6. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 6. ordered triple F G 8. Opposite vectors 9. terminal point 10. standard position 11. Sample answer: a directional measurement where the angle is measured clockwise from north 12. Sample answer: the sum of two or more vectors Chapter 8 7. C 8. J 9. D 10. H B: A16 〈36, -22, -16〉 Glencoe Precalculus Chapter 8 Assessment Answer Key Page 40 11. 1. B 2. H Form 2B Page 41 12. C H 1. B 2. J 13. B 3. C 3. 14. F 4. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 4. 5. A F 13. D 14. G 15. C C 16. J 6. H B 8. H 9. 12. J B 10. G Chapter 8 18. 19. J 7. D 8. G A 9. 10. A17 17. A 18. H 19. A 20. H D 20. H 45 57 27 , -− , -− − 〈 2 8 2〉 B: H H 17. A 7. B F 16. 6. 11. A 15. C 5. Page 42 H B: 〈270, 162, -180〉 Glencoe Precalculus Answers Form 2A Page 39 Chapter 8 Assessment Answer Key Form 2C Page 43 1. 2. Page 44 9.99 m, 0.35 m 〈 34 3 √ 34 5 √ 34 34 〉 - −, − 14. 15. 3. 6.0 cm, 219˚ 4. 116.6˚ 5. 〈-1, 15〉; 15.03 6. 17.5N; 63.8˚ south of east 16. 〈35, 52〉 17. 85 17 , -− 〈− 26 26 〉 18. 536.5 units2 19. 16.1 miles 183.2 J 〈18, 48, 28〉 145.4° 11. 20. 12. 13. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 〈28, -16, 15〉 9. 10. 660.2 mph 〈7, -21〉 7. 8. 38.8N, 48.9° 76.5 units3 −12, not orthogonal 6, not orthogonal Chapter 8 B: A18 180° Glencoe Precalculus Chapter 8 Assessment Answer Key Form 2D Page 45 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 2. 4.33 m, 2.5 m 〈 〉 -3 √ 73 8 √ 73 −, − 73 73 3. 2.2 cm, 43˚ 4. 53.1˚ 5. 〈-4, -1〉; 4.12 6. 20.4 N; 80.35˚ south of east 7. 14. 29.6 N, 58.4° 15. 616.4 mi/h 16. 〈30, 21〉 17. 111 74 , -− 〈− 13 13 〉 18. 655 units2 〈-3, 11〉 8. 〈1, -10, 7〉 9. 213.7 J 19. 10. 〈5, 13, 1〉 11. 97.7˚ 0, orthogonal −4, 13. not orthogonal Answers 1. Page 46 20.4 miles 20. 113.5 units3 B: 0˚ 12. Chapter 8 A19 Glencoe Precalculus Chapter 8 Assessment Answer Key Form 3 Page 47 Page 48 1. 10.57 m, 4.27 m 〈 √ 10 3 √ 10 -− , -− 10 10 2. 〉 0, orthogonal −8, not orthogonal 13. 12. 14. 3. 4.2 cm, 43˚ 4. 4.8˚ 5. 306.0 mi/h; about 52.5° 15. north of east 〈-1.9, 0〉; 1.9 20.4 N, 3.7˚ south of east 16. 〈-2, -19〉 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 6. 26.6 N, 51.6° 17. 〈-0.87, -0.61〉 7. 〈−23 , - −34 〉 8. 81 193 , -− , 4〉 〈− 2 8 18. 19. 250.3 units2 plane 2; 0.52 mi 607.1 N, 19.3˚ 9. north of east 10. 35 , 14, 14〉 〈- − 6 11. 57.4° 20. B: Chapter 8 A20 98.1 units3 180˚ Glencoe Precalculus Chapter 8 Assessment Answer Key Page 49, Extended-Response Test Sample Answers 1a. ⎢i j k⎢ 1h. 2 1 0 = 0i + 0j + 5k ⎢1 3 0 ⎢ B+C ⎢ C B B C ⎢ B+C 1b. a - b = a + (-b ), as shown in the figure below. 2a. 12.12 units -C 2b. 5.39 units B-C B 1c. Yes. They are the same diagonal of a parallelogram. 2c. second plane B B+C 3. Sample answer: The vectors a = 〈1, 0〉 and b = 〈0, -1〉 are perpendicular because their dot product is a1b1 + a2b2 = 1(0) + 0(-1) or 0; a = 〈5, 5〉 and b = 〈5, -5〉 are perpendicular because their dot product is a1b1 + a2b2 = 5(5) + 5(-5) = 25 - 25 = 0. C+B C B 1d. No. a - b and b - a are shown in the figures below. Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. C C− B −C −B B−C B 1e. Add the first terms of each vector together, and then add the second terms together. These terms represent the horizontal and vertical components of the resultant vector, respectively. c + d = 〈-3 + -8, 1 + (-11)〉, or 〈-11, -10〉 The magnitude of c + d is √ (-11)2 + (-10)2 , or about 14.9. 1f. Sample answer: 〈1, 2, 3〉 - 〈-3, 3, 0〉 = 〈4, -1, 3〉; 〈4, -1, 3〉 = 4i - j + 3k 1g. Sample answer: 〈3, 7〉; The vectors are perpendicular because their dot product is zero. a1b1 + a2b2 = 7 · 3 + (-3)7 = 0 Chapter 8 A21 Glencoe Precalculus Answers C Chapter 8 Assessment Answer Key Standardized Test Practice Page 50 1. A B C D 2. F G H J 3. 4. A F B G C H 11. A B C D 12. F G H J 13. A B C D 14. F G H J 15. A B C D 16. F G H J 17. A B C D 18. F G H J 19. A B C D 20. F G H J D J A B C D 6. F G H J 7. A B C D 8. F G H J 9. A B C D 10. F G H J A22 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 5. Chapter 8 Page 51 Glencoe Precalculus Chapter 8 Assessment Answer Key Standardized Test Practice (continued) Page 52 f(x) = 3 sin (6x) + 9 Copyright © Glencoe/McGraw-Hill, a division of The McGraw-Hill Companies, Inc. 22. x=5 23. 11.5 m/s, 32° 24. x = −2, y = 5 25. 66,221 J 26. 73.3° 27. CB = 17.8, A = 52.2°, B = 37.8°, C = 90° 28. 5.4 m/s, 36.2° Answers 21. (x – 9)2 + (y + 2)2 = 25 29. 30a. 〈45, 18, -1.5〉 30b. 〈-13, 28, -2〉 30c. Plane 2, 17.6 miles Chapter 8 A23 Glencoe Precalculus
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